SQL Bangla Tutorials

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eu (SQL) ( +  e  e '  (row) J   + ।e e  (row)e  , J   + ।): INSERT INTO test (id, first name, last name, email, course name,mobile) VALUES (8, 'Rahman', 'Abidur', ' [email protected]', ‘WDAD’, ‘01195229300’)

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SHOW TABLE ei sn 0 ( e     ( ) । DESCRIBE TABLE ei sn (  s  я+t ( ) ।) DESCRIBE test e0   0

(  TABLE ALTERATI ON

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2.alter table table_name ADD UNIQUE (col_name,...) 3.alter table table_name DROP PRIMARY KEY 4.alter table table_name ALTER [COLUMN] col_name {SET DEFAULT literal |DROP DEFAULT}

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AND,OR Operator e - # ,   condition    ) + ।) u( ,: u( , 1.SELECT * FROM Persons WHERE 2.LastName='Svendson' 3.AND (FirstName='Tove' OR FirstName='Ola')

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e ( ( \ e +  '#    a6= ( + । 1.SELECT productCode, FROM products 2.WHERE buyPrice NOT BETWEEN 20 AND 100

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1.select *

from DEPT where DEPTNO in (20,30)

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a0n QUERY ( SQL Joi n Tut or i al i n Bangl a)

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LastName

FirstName

Address

City

1

Hansen

Ola

Timoteivn 10

Sandnes

2

Svendson

Tove

Borgvn 23

Sandnes

3

Pettersen

Kari

Storgt 20

Stavanger

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OrderNo

P_Id

1

77895

3

2

44678

3

3

22456

1

4

24562

1

5

34764

15

k#   “O_Id” 0 “Orders”  Primary Key e6 e  “P_Id” ( “Persons”  # k( p(=  ,3  (    i।ei  ( 0 '# “P_Id” 0  '# e0 m 3।

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u( ,: Persons table P_Id

LastName

FirstName

Address

City

1

Hansen

Ola

Timoteivn 10

Sandnes

2

Svendson

Tove

Borgvn 23

Sandnes

3

Pettersen

Kari

Storgt 20

Stavanger

Orders table O_Id

OrderNo

P_Id

1

77895

3

2

44678

3

3

22456

1

4

24562

1

5

34764

15

“P_Id”( ( 0 m ) k e  - )(  # k(   ( i  ( order ) i ,    , INNER JOIN # ,      + । 1.SELECT Persons.LastName,Persons.FirstName,Orders.OrderNo 2.From Persons

3.INNER JOIN Orders 4.ON Persons.P_Id=Orders.P_Id 5.Order BY Persons.LastName

Result , e LastName

FirstName

OrderNo

Hansen

Ola

22456

Hansen

Ola

24562

Pettersen

Kari

77896

Pettersen

Kari

44678

INNER JOIN   (row) 2: + d  ) ( 0  '# +k e  - ।)( Persons table e  Orders table e   e  (row)   -   kt i  0 (  ।

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e   (table1) -     )(o a# (table_2,table_3...)  - e     - ।) 1.SELECT column_name(s) 2.FROM table_name1 3.LEFT JOIN table_name2 4.ON table_name1.column _name=table_name2.column_name

'   u+  - # k e6  ( k ( i      , 1.SELECT Persons.Lastname,FirstName,Orders.OrderNo 2.FROM Persons 3.LEFT JOIN Orders 4.ON Persons.P_Id=Orders.P_Id 5.ORDER BY Persons.LastName

Result ,    LastName

FirstName

OrderNo

Hansen

Ola

22456

Hansen

Ola

24562

Pettersen

Kari

77896

Pettersen

Kari

Svendson

Tove

44678

LEFT JOIN o  0 Left table(Persons) -   *   3 )(o Right table(Orders) e  - e

   i।

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e0 a# #  (table_2,table_3) -   )(o     - e     - ।) 1.SELECT Persons.Lastname,FirstName,Orders.OrderNo 2.FROM Persons 3.RIGHT JOIN Orders 4.ON Persons.P_Id=Orders.P_Id 5.ORDER BY Persons.LastName

e6 e 2 2    ( । LastName

FirstName

OrderNo

Hansen

Ola

22456

Hansen

Ola

24562

Pettersen

Kari

77896

Pettersen

Kari

44678 34764

SQL FULL JOI N e )(  # k k, e6 k  (  - # k ( i  ,    SELECT statement # ,   ,। 1.SELECT Persons.Lastname,FirstName,Orders.OrderNo 2.FROM Persons 3.FULL JOIN Orders 4.ON Persons.P_Id=Orders.P_Id 5.ORDER BY Persons.LastName

Result: LastName

FirstName

OrderNo

Hansen

Ola

22456

Hansen

Ola

24562

Pettersen

Kari

77896

Pettersen

Kari

44678

Svendson

Tove 34764