Ans Key Rbi Assistant Prelims 2017 PDF

Answer Key to RBI Assistant Prelims Live Leak 2017 Ques

1.

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10.

Ans

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Ques

11.

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Ans

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Ques

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Ques

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Ques

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50.

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Ques

51.

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Ans

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Ques

61.

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Ans

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72.

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75. 75.

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Ques. 71. Ans

1

Ques. 81. Ans

4

Ques. 91. Ans

4

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English Language Solutions: 1. The paragraph is pointing out the various data associated with banking in India since Independence, Independenc e, their growth/ decline, distribution and related figures. Thus option 2 is the correct answer. 2. Options 1,3 and 4 are complete opposites of what can be deciphered from the paragraph. Option 5 gives only one of the many things listed in the paragraph. Option 2 on the other hand lists all the key findings and is the correct answer. 3. The following sentence from the paragraph, ‘On the other hand only 15 per ce nt of

bank offices were located in towns with population of 10,000 and lesser.’ shows that option 5 is correct. 4. The word ‘comparatively’ in context of the given paragraph refers states that are better off in relation relation to other states. states. The other options options except ‘absolutely’ are synonyms of the given word. Thus, option 3 is the correct answer. 5. The following sentence in the given paragraph states It would be seen that out of the ‘

92 offices of the foreign banks, 75 offices were located in four States of the country i.e. Maharashtra, Maharasht ra, 23; West Bengal, 25; Delhi, 17; and Madras 10. Punjab and Kerala had 4

offices each,’ making option 1 is the correct answer. 6. The following sentence of the passage states that ‘Out of the remaining 68 scheduled

o ption 5 is the correct answer. banks 15 banks are of foreign origin.’ Hence option 7. The scheduled banks are 76 and these can be grouped under (i) the Public Sector; ‘

and (ii) the Private Sector’. From this sentence in the paragraph it is evident that option 2 is the answer. 2|Page

8. ‘Confidence’ in reference to the given paragraph means the act of faith or believe in

something. In this context, ‘reliance’ is the best fit answer. The other words relate to 'self confidence' and thus is not suitable in the context of the sentence. 9. ‘The reduction in the number of nonscheduled banks has been phenomenal -- from

473 to mere 33...’. From this sentence it can be concluded the solution 3 is the best fit answer. 10.. The following sentence of the passage states that ‘The Banking institutions in India 10 can be broadly grouped under two categories viz., (i) scheduled, and (ii) non-scheduled.’ Thus option 1 is the correct answer. 11. The passage is talking about the initiatives taken by the State Banks Staff Union to withdraw the merger merger of banks with with SBI. And then it it moves on to give some facts. facts. The meanings of the words mentioned in the options are as follows: 1.

‘Dissuade’: ‘persuade (someone) not to take a particular course of action.’

2.

‘Urge’: ‘try earnestly or persistently to persuade (someone) to do

something.’ 3.

‘Disinclined’: ‘unwilling’ or ‘reluctant’.

4.

‘Goad’: ‘provoke or annoy (someone) so as to stimulate an action or

reaction.’ 5.

‘Accredit’: ‘give credit to (someone) for something.’

We can easily eliminated ‘disinclined’ and ‘accredit’ as they are out of the context context of the passage. We can also eliminate ‘dissuaded’ because the decision to merge the banks has already been taken. We want a word that will go with ‘withdraw the efforts’ of this decision. We could have used ‘dissuaded’ if the decision wasn’t made or if wanted to say that they wanted to ‘dissuade’ the authorities from fr om the merger. But here they are talking 3|Page

about withdrawal of the merger. So it must be that they are encouraging the withdrawa withdrawall of the merger. This leaves us with two words – urged’ and ‘goaded’. ‘Goaded’ is a negative word, so it

can also be eliminated. Thus, ‘urged’, the usage of which conveys that the State Banks Staff Union has requested the Union government about something, makes a clear sense

when used in place of the first blank. Hence, the correct answer is ‘urged’. 12. Within 12. Within the context context of the given passage, passage, The State Banks Staff Staff Union urges the government and State Bank India to withdraw the merger of the five associate banks of

the latter. Such crucial information will be contacted to the ‘management’ rather than the ‘disciplinary committee’, ‘consultancy’ or the ‘staff’. ‘Office’ could have also filled the blank, but management is more apt in the context. Hence Hence ‘management’ is the correct answer. 13. Here the context is that of the SBI looking for merger of the Associate banks with SBI itself. Hence a reflexive pronoun has to be used in relation to it. Reflexive pronoun

for a singular subject is ‘itself’, which is the correct answer. 14. The State Banks Staff Union is an ‘organization’ that has raised concerns over the merger. An organization is a permanent structure as opposed to an assembly that gathers for a common purpose temporarily. Clearly the Union is a permanent structure

and hence cannot be termed an ‘assembly’. So, the correct answer is only ‘Organization’. l east 15. Logically, merging two banks would lead to ‘closure’ of several branches of at least one bank. Closure means ‘an act or process of closing something’. Thus, 3 is the correct answer. 16. Had option 4 been ‘announcement’ instead of ‘announce’, it could have been

considered as an apt choice. ‘Quote’ is also incorrect in correct as ‘quotes’ are not given with a purpose – rather they are parts of longer speeches and quotes are picked out of them to fit another context. Whenever something official is said by an official individual or a 4|Page

group, it is in the form of a ‘statement’ given to the press. Hence, ‘statement’ is the correct answer. 17. Clarification regarding an action by any organization is given either by the ‘officials’

or the ‘authorities’ of the organization. Hence, 5 is the correct answer. 18. The whole passage is talking about the effects of merging the banks which would be

in the form of shutting down of the banks. ‘Amalgamation’ ‘ Amalgamation’ also means the same as ‘merger’. Hence both ‘amalgamation’ and ‘merger’ can fit in the blank. Coalition is a willing union of two or more parties. In this case, the merger is not with the consent of the workers of the Associate banks, hence the merger cannot be called a

‘coalition’. ‘Severance’ which means ‘the action of ending a connection or relationship’ is an anton ym of ‘merging’. Hence option 5 is the correct answer. 19. All 19. All these are synonyms and fit fit the blank appropriately. appropriately. Hence, Hence, 5 is the correct correct answer. 20. The sentence suggests uncertainty about the exact number of banks as a numerical figure is mentioned after the blank. Hence ‘almost’ is the best fit for the blank. ‘Most’

and ‘several’ cannot be followed by a definite numerical figure. You can say: (1) There were several hundred people missing. missing. But you cannot say (2) There were several several four hundred people people missing. In the first case, they are talking about any number in the hundreds between 101 to 999.

So we can use ‘several’ before ‘hundred’. But ‘four hundred’ is a definite number and so ‘several’ cannot be used before it. ‘Informally’ does not fit the context and can be excluded. Hence, the correct answer is ‘almost’.

5|Page

21. The sun had set last evening and the artist recreated it later that night. This means that both the actions were in the past. So the use of the future tense in part 2 of the sentence is wrong. We need to correct this as follows – “The sight of the sun setting last

evening gave the artist…” 22. The wrong participle has been used to describe the baby. The baby is ‘unconcerned’ about everything else. The error is therefore in part 4 of the sentence. The word should

be the past participle and not present participle. participle. The corrected sentence would be “ How sweetly the baby sleeps in the mother’s lap unconcerned about everything else.” 23. The error lies in the part 3 of the sentence where ‘who’ needs to be replaced with

‘whom’. The relative pronoun ‘whom’ is used to further describe the object of the sentence ‘the only man in the whole campus’ so s o the form of the pronoun should be in a form that can replace the object. Thus the corrected sentence would read “ This is the only man in the whole campus whom you can trust completely.”

r elative pronoun. We are trying to describe the 24. ‘Where has’ is wrong usage of relative platform by saying that it has more than a million users. There are several ways to correct it-

(A) The platform that has has more than a million users… (B) The platform which has more than a million users… (C) The platform where there are more than than a million users… So the error is clearly in part 2 of the sentence. The best way to fix it would be in method (A). 25. ‘At’ is the wrong preposition to be used here. ISRO has tested the spacecraft using a

launch vehicle. ‘At’ indicates location while we want a preposition that indicates ‘instrument’. Hence, error is in part 1 of the sentence. ‘At’ should be replaced by ‘with’. 26. There is a wrong use of conjunction in the second part of the sentence. To suggest a contrast that is unexpected in light of the first clause, the conjunction ‘but’ is used. Thus 6|Page

the sentence must read – ‘Brexit may be a success but Britain does not fully understand its ramification ramifications. s. 27. You 27. You might be tempted tempted to mark 4 as the error. But that would would be wrong. Even though the sentence is in the past, the belief was taken to be a common fact and is hence stated in the simple present tense. The error is, in fact, in part 2 of the sentence. There are two ways to correct correct the sentence. sentence. Either: (A) In medieval Europe, Europe, it was believed believed that the sun… OR sun… OR (B)) In medieval Europe, it was a belief that the sun… (B 28. The tense in the given sentence is wrong. The sentence has a cause and effect structure. The effect is the closing down of prisons in Norway in the near future. So we use ‘will be shutting down’ in the future fut ure continuous tense. The cause, however, must precede the effect. The effect must have taken place sometime in the near past for it to be a direct cause to the effect. So we must use the present perfect tense. tense. The error is therefore in Part 3 of the sentence. sentence. It needs to be corrected to ‘as there haven’t been any’. 29. The error in the sentence is that there is a redundant use of conjunctions. We can either use ‘though’ or ‘but’ in the sentence, but we cannot use both. Since we cannot drop ‘though’ in the first part of the sentence since there is a comma (,) present in the second part after which , we must drop ‘but’ in the third part of the sentence. Thus the error is in part 3. 30. The error in the sentence is the mistake in the preposition used in part 4. The preposition ‘on’ should be changed to ‘by’. This is because the watch is an instrument through which we tell time. So you need to use the preposition ‘by’. Thus there is an error in part 4.

Numerical Ability 7|Page

31.. We will solve 31 solve both the equations separately. separately. Equation I:

1225  √ 4900 4900 = 0 √ 1225 ⇒ 35x + 70= 0 ⇒ x = (- 2) Equation II: (81)1/4 y + (343)1/3 = 0

⇒ 3y + 7 = 0 ⇒ y = - 7/3 = - 2.33 Comparing the values of x and y we get, x>y

32.. We will solve both the equations separately. 32 separately. Equation I: (729)1/3 l ÷ 423 = 1

⇒  /  = 1 ⇒ 9l = 423 ⇒ l = 423/9 = 47 Equation II: 6 × (3375)1/3m – (3240000)1/2 = 36

8|Page

⇒

6 × 15m – 1800 = 36

⇒

90m = 36 + 1800

⇒

m = 1836/90 = 20.4

Comparing the values of l and m we get, l>m

33.. We will solve 33 solve both the equations equations separately. separately. Equation I: p2 + p – 20 = 0 ⇒

p2 + 5p – 4p – 20 = 0

⇒

p(p + 5) - 4(p + 5) = 0

⇒

(p + 5) (p – 4) = 0

⇒

p = - 5, 4

Equation II. q2 – q – 30 = 0 ⇒

q2 – 6q + 5q – 30 = 0

⇒

q(q – 6) + 5(q – 6) = 0

⇒

(q – 6) (q + 5) = 0

⇒

q = 6, - 5

Comparing the values of p and q, we get, One value of q is greater than p and one is smaller. So, relation cannot be determined. 9|Page

34.. We will solve 34 solve both the equations equations separately. separately. Equation I:

a√25 + 2b = √961 Here √25 can only be evaluated e valuated as 5

⇒ 5a + 2b = 31 Equation II: 3a + (2401)1/4 b = 36

⇒ 3a + 7b = 36 Multiplying the simplified simplified values of equation (I) by 3 and that of (II) by 5, we get, b = 3 Putting this value of y in the simplified value of equation (I), we get a=5

∴ a > b 35.. We will solve 35 solve both the equations equations separately. separately. Equation I: (l1/4 ÷ 16)2 = 144 ÷ l3/2 Taking square root of both the sides

/

⇒ / = ( ) 10 | P a g e



⇒  =   ⇒     = 12 12 × 16 ⇒ l = 192 Equation II: m1/3 × m2/3 × 3104 = 16 × m2

⇒  + × 3104 = 16 ×  ⇒ m × 3104 = 16 × m ⇒ m = 3104/16 ⇒ m = 194. 2

Comparing the values of l and m, we get, l
36.. The length of a rectangular 36 rectangular plot is thrice thrice its breadth. Assume that the the breadth of the rectangular rectangular plot is D meter. According to the question, the length length of a rectangular rectangular plot is thrice thrice its breadth. The length is 3D meter. Area of the plot = length length × breath According to the question, the area area of the rectangular plot plot is 7803 sq. meter. meter.

⇒ 7803 = 3D × D ⇒ 7803 = 3D2 11 | P a g e

⇒ D = 51 meter ∴ Breadth of the plot = 51 meter 37.. Tap fills the 37 the cistern in in 15 hours

∴ part of cistern filled by the tap in 1 hour = 1/15 With the leak tap fills fills the cistern cistern in 5 hours more, more, i.e. in 20 hours

∴ part of cistern filled by the tap in 1 hour with the leak = 1/20 =      =  ∴ in 1 hour liquid flowing out through the leak The full liquid will flow out through the leak in 60 hours

38.. Let the first number be ‘n 1’,second number be ‘n2’ and the third number be ‘n 3’ 38

∵ Average of the first 3 numbers = 17 ∴ ++ = 17 ∴ n + n + n = 51 ------(1) 1

2

3

Also, the average average of the last 3 numbers numbers is 14

∴ ++ = 14 ∴ n + n = 42 – 19 ∴ n + n = 23 ∴ Substituting the value of (n + n ) in equation (1) we get, 2

3

2

3

2

12 | P a g e

3

⇒ n + 23 = 51 ∴ n = 28 1

1

Thus the first number is 28

39.. Let assume 39 assume the age of of the girl girl is x years. years. We know, Average of of quantities =sum of of all quantities/no. quantities/no. of quantities Three years ago, the average age of a family of 4 members was 14 years.

∴ Sum of ages of all four family members members three years ago = 14 × 4 = 56 years Today, each of the four member ages by 3 years.

∴ the total age of the 4 members of the family = 56 + (4 × 3) = 68 years. A girl having been born, born, the average of the family family is the same same today i.e. 14 years.

∴ 14 = (68 + x)/5 ⇒ 68 + x = 70 ⇒x=2 ∴ The age of the girl is 2 years. 40.. According to the given information, 40 We know that, Efficiency × Time Taken = Work Done Here, work done is checking the answer papers. In the first case, let’s assume the work

done to check the certain number of answer papers is ‘1’ 13 | P a g e

Number of examiners = 4 Number of working hours = 10 × 5 = 50 hours All the examiners examiners are equally efficient. efficient.

Let’s assume the efficiency of one examiner to be ‘E’

⇒ 4E × 50 = 1 ⇒ E = 1/200 In the second case, let’s assume the number of working hours to be ‘t’ The work to be done is doubled because number of answer papers papers are doubled.

⇒ 2E × t = 2 ∵ t = 1/E = 200 hours ∵ No. of days = 20 ∴ No. of working hours a day = 200/20 = 10 hours 41.. The pattern 41 pattern of given series is : →

8,

→

8 + (3)1 = 11,

→

11 + (3)2 = 20,

Here to satisfy the pattern of series 17 is replaced by 20 →

20 + (3)3 = 47,

→

27 + (3)4 = 128,

→

128 + (3)5 = 371,

14 | P a g e

→

371 + (3)6 = 1100

∴ the wrong term is 17. 42.. The given 42 given series series is, is, →

1,

→

2 = 1 + 30,

→

5 = 2 + 3,

→

14 = 5 + 32,

→

41 = 14 + 33,

→

122 = 41 + 34

∴ The wrong number is 124. 43.. The given 43 given series series is, is, →

325,

→

259 = 325 – 11 × 6,

→

204 = 259 – 11 × 5,

→

160 = 204 – 11 × 4,

→

127 = 160 – 11 × 3,

→

105 = 127 – 11 × 2,

→

94 = 105 – 11 × 1

∴ The wrong term is 202. 15 | P a g e

44.. The given 44 given series series is is 16

24

48

120 ? 1260

Search for pattern: 16

24

48

120

?

16/2 = 8 and 8 × 3 = 24 24/2 = 12 and 12 × 4 = 48 48/2 = 24 and 24 × 5 = 120 120/2 = 60 60 and 60 × 6 = 360 360/2 = 180 and 180 × 7 = 1260 Thus, the required number be 360 45.. 45 →

4,

→

7,

→

11 = 4 + 7,

→

18 = 11 + 7,

→

29 = 18 + 11,

→

47 = 29 + 18,

→

Next number = 47 + 29 = 76,

→

123 = 76 + 47,

→

199 = 123 + 76

16 | P a g e

1260

46.. Let the length 46 length of the cone cone be X Given, Width of the canvas = 3 m Slant height of the conical tent (l) = 4.9 m Diameter of the conical tent (d) = 12 m

∴ Radius of the conical tent (r) = d/2 = 12/2 = 6 m ∴ Area of the canvas = length × width = 3X m ∴ Curved surface area of the conical tent =  =  × 6 × 4.9 = 92.4  ∵ Area of the canvas = Curved surface area of the conical tent ⟹ 3X = 92.4 ⟹ X = 30.8 ∵ Length of the cone= 30.8 m 2

47. In organization D number of Males = 3250 In organization D number of Females = 2750 The ratio of the number of females to the number of males from Organizations Organizations D = 2750 : 3250 = 275 : 325 = 11 : 13 Hence the answer is 11:13 17 | P a g e

48.. The number of females 48 females in organization organization E = 2750 The number of males in organization E = 2500 Total number of employees in organization E = 2750 + 2500 = 5250 The number of females in the Organizations E will forms the percent of the total number of employees form that organization is =

    ×100      ×100  = 52.38 Hence the answer is 52.38

49.. The number of female 49 female employees in Organization Organization A = 1500 The number of male employees in Organization A = 1750 The total number of employees in Organization A = 1500 + 1750 = 3250 The number of female employees in Organization C = 2500 The number of male employees in Organization C= 2500 The total number of employees in Organization C = 2500 + 2500 = 5000 The total number of employees working in organisations organisations A and C together = 3250 + 5000 = 8250 18 | P a g e

Hence the answer is 8250

50.. The number of female 50 female employees in Organization Organization B = 2250 The number of male employees in Organization B = 2000 The total number of employees in Organization B = 2250 + 2000 = 4250 The number of females in the Organizations B will forms the percent of the total number of employees form that organization is =

       ×100      .  ×100  = 52.94

≈ 53 %

51.. The number of male 51 male employees employees in Organization Organization A = 1750 The number of male employees in Organization B = 2000 The number of male employees in Organization C= 2500 The number of male employees in Organization D= 3250 The number of male employees in organization E = 2500 The total number of males from all the organisations together = 1750 + 2000 + 2500 + 3250 + 2500 = 12000 Hence the answer is 12000 19 | P a g e

52.. Let Investment of C is ‘x’. 52

Then investment of B = 800 + C’s investment = 800 + x Investment of A = 700 + B’s investment = 700 + (800 + x) = 1500 + x Total sum invested in the business = Rs 5,000

⇒ Investment of (A + B + C) = Rs. 5,000 ⇒ 1500 + x + 800 + x + x = 5,000 ⇒ 2300 + 3x = 5000 ⇒ 3x = 2700 ⇒ x = 900 Such that

A’s investment = 1500 + x = 1500 + 900 = 2,400 Rs. B’s investment = 800 + x = 800 + 900 = 1,700 Rs. C’s investment = x = 900 Rs. Ratio of A: B : C = 2,400 : 1700 : 900 = 24 : 17 : 9 Sum of all the ratio’s = 9 + 17 + 24 = 50 Share of B out of profit of Rs. 1500

= 150 15000 ×  = 510 . 53.. Let there is C amount of 53 of Copper in the mixture mixture for 1 amount of gold. 20 | P a g e

Given 15 is the relative density of mixture w.r.t water. Volume of mixture mixture = 1 + C Mass of the mixture = 19 + 9C

⇒ 19 + 9C = 15 × (1+C) ⇒ 4 = 6C ⇒ C = 4/6 = 2/3 ∴ Ratio of Gold to Copper = 1: C = 1: 2/3 = 3: 2 54.. 54

  56%  550 = ?  = ¾ × 56% × 550

 ×550 =  ×   ×550 = 3 ×  = 3 × 14 × 5.5 = 42 × 5.5 = 231

55.. Given Equa 55 Equation tion isis-

⇒ 30492 ÷ √? = 77 × 12 21 | P a g e

⇒ 30492 ÷ √? = 924 ⇒ √? = 30492 / 924 = 33 ⇒ ? = (33) = 1089 2

Hence the answer is 1089.

56.. Given expres 56 expression sion:: 73% of 650 – 111% of 240 = [73% of 650] – [111% of 240]

 × 650] [ ⇒ [   [  ×240] = [73 × 6.5] – [111 × 2.4] = 474.5 – 266.4 = 208.1

57.. Given Equat 57 Equation ion is, is,

⇒ (2 ) × 3 – (5 – 2 ) =? ⇒ 2 × 27 – (25 – 4) = ? ⇒ ? = 2 × 27– 21 ⇒ ? = 512 × 27 - 441 ⇒ ? = 13,824 – 441 ⇒ ? = 13,383 3 3

3

2

2 2

3×3

2

9

2

Hence, the required answer is 13,383 22 | P a g e

58.. Giv 58 Given en that, that, Amount = Rs 5984, 5984, Principal = Rs 4400 4400

∴ Simple interest (S.I.) = amount – principal = Rs (5984 – 4400) = Rs 1584 Rate of interest r = 4% We know that:

..= ××  Where, S.I. = Simple Interest P= principal T = Time R = Rate of interest Now, according to the question, Required time = (1584 × 100)/(4400 × 4) = 9 years Hence, the required time is 9 years.

59.. A man sells two watches 59 watches for Rs. 199 each. On one he gained 10 p.c. and on the other he lost 10 p.c. Selling price (SP) of one watch = Rs 199 Let Cost price (CP) = Rs x 23 | P a g e

Gain % = 10 %

 % = −  ×100% ⇒ 10 = −  ×100 ⇒ 10(x) = (199 - x)× 100 ⇒ 10 x = 19900 – 100x ⇒ 110x = 19900 ⇒ x = 180.9 Rs Now

Selling price (SP) of another watch = Rs 199 Let Cost price (CP) = Rs x Loss % = 10 %

% = −  ×100% ⇒ 10 = −  ×100 ⇒ 10(x) = (x - 199) × 100 ⇒ 10 x = 100x - 19900 ⇒ 90x = 19900 ⇒ x = 221.1Rs Now

Total selling price = Rs199 + Rs. 199 = Rs. 398 Total Cost Price = Rs. 180.9 + Rs. 221.1 = Rs. 402

 % = −   ×100% ⇒   % = − 100%% = 0.99 0.99%% ≃ 1%    × 100 Now

24 | P a g e

60.. Form 60 Formulas ulas to be be used:used:SI, SI = (P × r × t)/100 t) /100 For CI:

   =  1   Where SI is Simple Simple interest, A is the amount at the the end of time t, P is the principal, t is time in years. r is annual rate of interest A man borrowed borrowed Rs. 800 at 10% 10% p.a. SI for 2 years. years.

∴ SI = (800 × 10 × 2)/100 ⇒ SI = 160 Thus amount which he has to return = P + SI = 800 + 160 960 ⇒ Amount which he has to return = 960 He lent the whole sum, i.e., Rs. 800 he borrowed at 10 % p.a. CI for 2 years.

  ∴ Amount which he will receive = 800 1  ⇒ A = 800 × 1.1 ⇒ A = 968 ∴ Amount he earns = 968 -960 = Rs. 8 2

25 | P a g e

61.. Fo 61 Foll llow ow BODMAS BODMAS rule rule to solve this question, as per the order given below, Step-1-Parts Step-1Parts of an equation enclosed in 'Brackets' must be solved first, Step-2- Any mathematical mathematical 'Of' or 'Exponent' 'Exponent' must be solved solved next, Step-3-Next, Step-3Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, Step-4-Last Step-4Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated. Now, given expression:

⇒ (40% of 1,965 × 74) ÷ ? = 4,847 ÷ 2 ⇒ (0.4 × 1,965 × 74) ÷ ? = 4,847 ÷ 4 ⇒ (786 × 74) ÷ ? = 1211.75 ⇒ 58164 ÷ ? = 1211.75 ⇒ ? = 58164/1211.75 ⇒ ? = 48

2

Hence, the required answer is 48

62.. 62

{ =   } ⇒ Speed of the first train 15015 = 10  Total length of both trains = 300 m

26 | P a g e

Total time = 12 seconds

   25  ∴ Total speed =      ∴ Speed of the second train = Total speed – Speed of the first train = 25 – 10 = 15 m/s =

15 ×  ℎ = 54 ℎ

63.. Let us assume that `x’, `y’ and `z’ be the three numbers. 63 Sum of three numbers = 98

∴ x + y + z = 98 ………..(1) Given that the ratio of first number to the second = 2:3

⇒ x/y = 2/3 ⇒ x = 2y/3 …………(2) Similarly the ratio of second number to the third = 5:8

⇒ y/z = 5/8 ⇒ z = 8y/5 ………….(3) Substituting (2) and (3) in (1), we get

⇒      = 98 ⇒ 49y/15 = 98 ⇒ y = 30 ∴The second number is 30 27 | P a g e

64.. 64 Let's Assume there are 20 poles named P 1 to P20, also it is given that the poles are placed at equal distances between them, Let the distance between 2 consecutive poles is x

⇒ If the car is at 2nd Pole or Pole P the Distance covered by the car is x ∴ When the Car is at pole 12 or P the distance covered by the car is 11x ⇒ Speed × Time = Distance 2

12

Given time taken to reach 12th Pole = 24 secs. Let the Speed of the Car = S m/sec And Distance Distance Covered = 11x

⇒ (11x) = 24 × S .... (i) Similarly

∴ When the Car is at pole 20 or P

20 the

distance covered by the car is 19x

Speed × Time = Distance Let time taken to reach 20th Pole = t secs. Speed of the Car = S m/sec And Distance Distance Covered = 19x

⇒ (19x) = t × S .... (ii) ⇒ From Equations (i) & (ii) ⇒ 19x = t × (11x / 24) ⇒ t = (19/11) × 24 ⇒ t = 41.45 secs 28 | P a g e

65.. Total number of letter in the word ELATION = 7 65 Vowels = EAIO Consonant = LTN In the first place we have 4 choices and then in the last place we have 3 choices In the remaining 5 place we are to arrange 5 letters in 5p5 ways

∴ total number of rearrangem rearrangements ents possible = 4 × p ⋅ 3 5 5

=4×5×4×3×2×1×3 = 1440

Reasoning Ability 66.. Given series is: 258 66

427

753

684

892

On replacing first digit by third digit and second by first digit and third digit by second digit

→

825

742

375

468 468

289

Now 289 is the smallest number which is obtained by interchanging digits of 892. Hence 892 is the answer. 67. Given series is: 258

427 753

684

892

On arranging them in descending (decreasing) order

→

892 753 684 427 258

Now third digit of 2nd number (753) is 3 and second digit of 3rd number (684) is 8 Difference between them = 8 – 3 = 5. 68. Given series is: 258

427 753

On interchanging 1st and 2nd digits

→

684 528

892 247

573

864

982

Now smallest number is 247 which is obtained by interchanging digits of 427. 29 | P a g e

Hence 427 is the answer. 69. Given series is: 258

427

753

On interchanging 1st and 3rd digits

→

684 852

892 724

357

486

298

Clearly 852 is the largest which is obtained by interchanging interchanging 258. Hence 258 is the answer. 70. 70. Given series is: 258

427 753

684

892

On subtracting ‘1’ from middle digit of each number n umber the series become: 248

417

743

674

882

On arranging them in Descending (Decreasing) order

→

882

743

674

417

248 Newly formed second second number from left is 743 and sum of its digits = 7 + 4 + 3 = 14. 71. 71. On word ERQHKA, ERQHKA, none of the conditions apply, hence, hence, we can code it simply using the table. Letters Digits/Symbols Conditions

P

M

A

E

J

K

D

4

$

1

2

3

#

5

@

Q

H

I

U

T

F

©

6

%

δ

7

9

E = 2, R = @, Q = ©, H = 6, K = #, A = 1 Hence, 2 @ © 6 # 1 is the answer. 72. 72. Letters

P M A E J

Digits/Symbols Digits/Symbols Conditions 4

30 | P a g e

$ 1

2

3

K D R Q H I # 5

U T F

@ © 6 % δ

7

9

In the word MPEKDU, we can see that the first letter is a consonant and last letter is a vowel so the condition condition 1 applies here here we have to interchange interchange first and last last letter

We can see, Code of MPEKDU without condition from the table is $42#5δ. Now we apply condition 1 and final answer becomes δ 4 2 5 # $ Hence, δ 4 2 5 # $ is the answer. 73. 73. Letters

P M A E J


$ 1

2

3

K D R Q H I # 5

U T F

@ © 6 % δ

7

9

In the word TMEIUF, we can see that both the first and the last letter are consonants so condition 2 is applicable here i.e. both first and last letter are to be coded as the last letter.

From the table, the simple code for TMEIUF becomes 7$2%δ9, after condition 2 it becomes 9$2%δ9. Hence, 9$2%δ9 is the answer. 74. 74. In the word JTAERI, we can see that first letter letter is a consonant and last last letter is a vowel so condition condition 1 applies here; here; we have to interchange interchange first and last last letter. Letters

P M A E J


$ 1

2

3

K D R Q H I # 5

U T F

@ © 6 % δ

7

9

We can see from the table that Code of JTAERI without condition condition is 3712@%, now now we apply condition 1 and final answer becomes %712@3. Hence, %712@3 is the answer.

31 | P a g e

75. 75. In the word UKTMIH, we can see see that first letter is a vowel and the last letter is a consonant hence condition 3 is applicable here that is both first and last letter is to be

⋆

coded as . Letters

P M A E J


$ 1

2

3

K D R Q H I # 5

@ © 6 % δ

⋆

⋆

UKTMIH is coded as δ# 7 $ % 6. After applying condition, # 7 $ % .

⋆

⋆

Hence, # 7 $ % is the answer. 76.. Here right turn means 76 means going in clockwise clockwise direction. direction.

Total distance walked walked by Sourabh = 5 + 7 + 10 + 6 + 5 = 33m. 77. 77. Here right turn means means going in clockwise clockwise direction. direction. 32 | P a g e

U T F 7

9

Clearly Point H is 1m towards east of point M. 78. 78. Here, in a joint family of seven persons persons L, M, N, O, P, Q and R two are married couples.

1) ‘R’ is a housewife and her her husband is a lawyer.

2) ‘N’ is the the wife wife of ‘M’. ‘M’. 3) ‘L’ is an engineer and is the granddaughter of of ‘R’. 4) ‘O’ is the fathe fatherr-in-law of ‘N’, a doctor, and father of ‘P’, a professor.

33 | P a g e

‘Q’ is L’s brother and M’s son:

Gender of ‘P’ is not known. Thus data is inadequate. 79.. Here, in a joint family of seven persons L, M, N, O, P, Q and R two are married 79 married couples.


2) ‘N’ is the the wife wife of ‘M’. ‘M’. 3) ‘L’ is an engineer and is the the granddaughter of ‘R’. 34 | P a g e

4) ‘O’ is the fathe fatherr-in-law of ‘N’, a doctor, and father of ‘P’, a professor.


Therefore, Q is the grandson of O.

80. 80. Here, in a joint family of seven persons persons L, M, N, O, P, Q and R two are married couples.


2) ‘N’ is the the wife wife of ‘M’. ‘M’. 35 | P a g e

3) ‘L’ is an engineer and is the granddaughter of of ‘R’. 4) ‘O’ is the fathe fatherr-in-law of ‘N’, a doctor, and father of ‘P’, a professor.


Therefore, O is father of M. 81. 81. According According to the question, we have have 7 individuals – Alan, Barton, Dana, Kyle, Peter, Remus and Sarah. Considering the information provided in the question: Sarah weights more than Barton and Alan. Hence Sarah > (Alan, Barton). Remus weights less than only Kyle. Hence Kyle is the heaviest followed by Remus at second place. Kyle > Remus > Sarah > (Alan, Barton)

36 | P a g e

Peter weights as much as Sarah but less than Dana. Hence Dana is heavier than everyone except Kyle and Remus. Kyle > Remus > Dana > Peter = Sarah > (Alan, Barton) Alan does not weigh weigh the minimum. minimum. Hence Alan is heavier heavier than Barton. Barton. Kyle > Remus > Dana > Peter = Sarah > Alan > Barton So the final arrangement arrangement is: Kyle > Remus > Dana > Peter = Sarah > Alan > Barton Hence we can conclude that Dana is the 3rd heaviest individual.

82. 82. According According to the question, we have have 7 individuals – Alan, Barton, Dana, Kyle, Peter, Remus and Sarah. Considering the information provided in the question: Sarah weights more than Barton and Alan. Hence Sarah > (Alan, Barton). Remus weights less than only Kyle. Hence Kyle is the heaviest followed by Remus at second place. Kyle > Remus > Sarah > (Alan, Barton) Peter weights as much as Sarah but less than Dana. Hence Dana is heavier than everyone except Kyle and Remus. Kyle > Remus > Dana > Peter = Sarah > (Alan, Barton) Alan does not weigh weigh the minimum. minimum. Hence Alan is heavier heavier than Barton. Barton. Kyle > Remus > Dana > Peter = Sarah > Alan > Barton So the final arrangement arrangement is: Kyle > Remus > Dana > Peter = Sarah > Alan > Barton Hence we can conclude that: Only one person is heavier than Remus Peter weighs more than Barton No one weighs less than Barton No one is heavier than Kyle

Hence the answer is ‘No one weighs less than Barton’. 37 | P a g e

83. 83. Statement Statement:: T < U ≤ P; R ≤ N ≤ U < H = S Let us check each conclusion one by one. I) T < S

⇒ T < U < H = S ⇒ T < S True as U ≤ P; R ≤ N ≤ U ⇒ R ≤ N ≤ U ≤ P ⇒ R ≤ P False as U ≤ P; R ≤ N ≤ U ⇒ R ≤ N ≤ U ≤ P ⇒ R ≤ P False

as T < U; U < H = S

→

II) II) P = R

→

→

III) III) R < P

→

→

→

Now since conclusions (II) and (III) together are true, so they will form pair and either case will be true. Therefore, only (I) and either (II) or (III) follow.

84. 84. Statement: U > Y < W; M < Y > I ≥ K = O ≥ L Let us check each conclusion one by one.

⇒ W > M True II) II) L ≤ I as I ≥ K = O ≥ L ⇒ I ≥ L True III) III) U > O as U > Y; Y > I ≥ K = O ⇒ U > Y > I ≥ K = O ⇒ U > O

I) W > M

as Y < W; M < Y

→

→

→

→

→

True

→

Therefore all conclusions are true.

85. 85. Given Given statement statements: s:

R ≤ J > M, J ≥ L = S < N, S ≥ P On simplifying:

R ≤ J, J > M, J ≥ L = S ≥ P, L = S < N Conclusions:

I. P ≤ J

Clearly True (as J ≥ L = S ≥ P

→

II. II. R = L

False (as R ≤ J and J ≥ L

→

cannot be determined)

38 | P a g e

J ≥ P)

→

R ≤ J ≥ L

→

clear relationship between R and L

→

III. III. M < N

≥ L < N

→

False (as J > M, J ≥ L and L = S < N, so we get, M < J ≥ L = S < N

clear relationship between M and N cannot be determined)

→

Hence only conclusion I is true.

86.. People: Anagha, 86 Anagha, Kirti, Garima, Garima, Sanchit, Ronit and and Aditya. Profession: Fashion Designer, Businessman, Businessman, Financial Analyst, Engineer, CA and Doctor. Belongs to: Haryana, Hyderabad, Ranchi, Jodhpur, Mumbai and Chennai. We can make the the following diagram diagram according to information information given. 1) The Fashion Designer Designer and the Businessman are are sitting opposite to each other.

2) The Financial Financial Analyst is to be immediate right of of the CA. Two cases can be formed:

39 | P a g e

M < J

→

3) The Doctor, from Haryana, Haryana, is to the immediate left of the Businessman. Businessman. It means Case 2 will be considered. Now as only Engineer is left, it occupies the vacant place.

4) The person from Ranchi Ranchi and Mumbai are sitting opposite opposite to each other and neither of them is a Fashion Designer. 40 | P a g e

It means they can only be Engineer and CA.

5) Garima is from Ranchi Ranchi and is to the immediate left of the person person from Hyderabad. Thus only CA or Engineer can be from Ranchi. If Garima is sitting to the immediate left of the person from Hyderabad then Garima must be CA.

41 | P a g e

6) Anagha and Sanchit Sanchit are sitting opposite each other and neither neither of them is from Hyderabad.

7) Anagha is to the immediate immediate left of Aditya. Aditya.

Thus the Final Diagram: 42 | P a g e

We can see that that Ronit and Kirti are are sitting opposite to each each other. 87. 87. People: Anagha, Anagha, Kirti, Garima, Sanchit, Sanchit, Ronit and Aditya. Profession: Fashion Designer, Businessman, Businessman, Financial Analyst, Engineer, CA and Doctor. Belongs to: Haryana, Hyderabad, Ranchi, Jodhpur, Mumbai and Chennai. We can make the the following diagram diagram according to information information given. 1) The Fashion Designer Designer and the Businessman are are sitting opposite to each other. other.

43 | P a g e

2) The Financial Financial Analyst is to to be immediate right of the the CA. Two cases can be formed:

3) The Doctor, from Haryana, Haryana, is to the immediate left of the Businessman. Businessman. It means Case 2 will be considered. Now as only Engineer is left, it occupies the vacant place. 44 | P a g e

4) The person from Ranchi Ranchi and Mumbai are sitting opposite opposite to each other and neither of them is a Fashion Designer. It means they can only be Engineer and CA.

5) Garima is from Ranchi Ranchi and is to the immediate left of the person person from Hyderabad. Thus only CA or Engineer can be from Ranchi. 45 | P a g e

If Garima is sitting to the immediate left of the person from Hyderabad then Garima must be CA.


7) Anagha is to the immediate immediate left of Aditya. Aditya. 46 | P a g e

Thus the Final Diagram:

The Doctor is sitting to the immediate right of Engineer. 88. 88. People: Anagha, Anagha, Kirti, Garima, Sanchit, Sanchit, Ronit and Aditya. 47 | P a g e

Profession: Fashion Designer, Businessman, Financial Analyst, Engineer, CA and Doctor. Belongs to: Haryana, Hyderabad, Ranchi, Jodhpur, Mumbai and Chennai. We can make the the following diagram diagram according to information information given. 1) The Fashion Designer Designer and the Businessman are are sitting opposite to each other. other.


48 | P a g e


4) The person from Ranchi Ranchi and Mumbai are sitting opposite to each other other and neither of them is a Fashion Designer. 49 | P a g e



50 | P a g e




The person sitting to the immediate right of the person from Jodhpur is from Mumbai. 89.. People: Anagha, 89 Anagha, Kirti, Garima, Garima, Sanchit, Ronit and and Aditya. Profession: Fashion Designer, Businessman, Financial Analyst, Engineer, CA and Doctor. Belongs to: Haryana, Hyderabad, Ranchi, Jodhpur, Mumbai and Chennai. We can make the the following diagram diagram according to information information given. 1) The Fashion Designer Designer and the Businessman are are sitting opposite to each other. other.

52 | P a g e


3) The Doctor, from Haryana, Haryana, is to the immediate left of the Businessman. Businessman. It means Case 2 will be considered. Now as only Engineer is left, it occupies the vacant place. 53 | P a g e

4) The person from Ranchi Ranchi and Mumbai are sitting opposite opposite to each other and neither of them is a Fashion Designer. It means they can only be Engineer and CA.

5) Garima is from Ranchi Ranchi and is to the immediate left of the person person from Hyderabad. Thus only CA or Engineer can be from Ranchi. 54 | P a g e

If Garima is sitting to the immediate left of the person from Hyderabad then Garima must be CA.


7) Anagha is to the immediate immediate left of Aditya. Aditya. 55 | P a g e

Thus the Final Diagram:

The person sitting to the immediate right of Aditya could be Kirti or Ronit. 90. 90. People: Anagha, Kirti, Kirti, Garima, Sanchit, Sanchit, Ronit and Aditya. 56 | P a g e

Profession: Fashion Designer, Businessman, Financial Analyst, Engineer, CA and Doctor. Belongs to: Haryana, Hyderabad, Ranchi, Jodhpur, Mumbai and Chennai. We can make the the following diagram diagram according to information information given. 1) The Fashion Designer Designer and the Businessman are are sitting opposite to each other. other.


57 | P a g e


4) The person from Ranchi Ranchi and Mumbai are sitting opposite opposite to each other and neither of them is a Fashion Designer. 58 | P a g e



59 | P a g e




If Ronit is from Haryana, profession of Kirti is Financial Analyst. 91. 91. Eight family members members P, Q, R, S, T, U, V and W are sitting in a row facing north. Note: Four of them are males. There are three couples in the family.

61 | P a g e

Let us draw a straight line and mark 8 persons who are facing north.

1) T sits second second to the right of V. 2) Q is on the immed immediate iate left left of V. 3) S is second second to left left of Q. Q. Thus we get 3 possibilities,

62 | P a g e

4) S is wife of W and sits adjacent to her husband. 5) P is brother of W, who who is on the immediate immediate right of P. Were possibility possibility 1 and 2 are not possible. possible.

6) U is not not a neighbour neighbour of V.

Now let us draw family tree. 7) T is a male and sits sits second to the right right of V, who is wife of of R.

8) Q is a female and sits second second to the left of her father in law. It means R is father in law of Q. 63 | P a g e

9) S is wife of of W. U is daughter daughter of W.

10) P is brother of W, T and and U are siblings, siblings, T is a male.

Now combine both family trees,

Now we can mark the male and female members in the line as:

64 | P a g e

Clearly there are four females between R and W.

92. 92. Eight family members members P, Q, R, S, T, U, V and W are sitting in a row facing north. Note: Four of them are males. There are three couples in the family.


1) T sits second to the right of V. 2) Q is on the immed immediate iate left left of V. 3) S is second second to left left of Q. Q. Thus we get 3 possibilities, 65 | P a g e


6) U is not a neighbou neighbourr of V.







67 | P a g e

Clearly U sits second to left of V and U is the granddaughter of V. 93. 93. Eight family members members P, Q, R, S, T, U, V and W are sitting in a row facing north. Note: Four of them are males. There are three couples in the family.


1) T sits second second to the right of V. 2) Q is on the immed immediate iate left left of V. 3) S is second second to left left of Q. Q. Thus we get 3 possibilities, 68 | P a g e


6) U is not a neighbo neighbour ur of V.







70 | P a g e

Clearly R is third to the right of S’s daughter U. 94. 94. Eight family members members P, Q, R, S, T, U, V and W are sitting in a row facing north. Note: Four of them are males. There are three couples in the family.


1) T sits second second to the right of V. 2) Q is on the immed immediate iate left left of V. 3) S is second second to left left of Q. Q. Thus we get 3 possibilities, 71 | P a g e









73 | P a g e

Clearly VQ is different from others as second person is sitting to the immediate left of first person whereas in other options second person is sitting to the immediate right of first person. 95.. Eight family members 95 members P, Q, R, S, T, U, V and W are sitting in a row facing north. Note: Four of them are males. There are three couples in the family.


1) T sits second second to the right of V. 2) Q is on the immed immediate iate left left of V. 3) S is second second to left left of Q. Q. 74 | P a g e

Thus we get 3 possibilities,




75 | P a g e

8) Q is a female and sits second second to the left of her father in law. It means R is father in law of Q.




Now we can mark the male and female members in the line as: 76 | P a g e

Clearly S is third to the left of V (Mother-in-law of S). 96-100. 96-100. Candidates: A, G, L, N, P, Q, R and S [5 males, 3 females] Banks: BOB, BOI, Dena Bank, UBI, OBC, Indian Bank, Corporation Bank and UCO City: Jaipur, Delhi, Noida, Kanpur, Patna, Ranchi, Gurgaon and Ghaziabad 1. P has applied for Indian Indian Bank from Ghaziabad. Ghaziabad. G has applied for OBC. His sister L has applied for Dena Bank from Jaipur.

⇒ G is male,

L is female. N has applied for UBI. (And her friend)

⇒ N is female.

Q is from Gurgaon and has not applied either for Corporation Bank or for UCO Bank. S has applied from Kanpur. A does not apply from Patna. Person

Gender

Bank

A

City Patna ×

G

M

OBC

L

F

Dena

N

F

UBI

Jaipur

P

Indian Bank

Ghaziabad

Q

Corporation × UCO × Gurgaon

R S

Kanpur

2. No male has applied applied from Ranchi Ranchi and Kanpur.

⇒ S is female, all else are male.

Also, N is from Ranchi (only female female left) Person 77 | P a g e

Gender

Bank

City

A

M

Patna ×

G

M

OBC

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M


R

M

S

F

Kanpur

3. Only bank left for Q are BOB or BOI BOI but the one who belongs to Delhi has applied for BOB.

⇒ Q applied for BOI. Only cities left: Delhi, Noida and Patna. The one who has applied for UCO Bank has applied neither from Patna nor from Noida.

⇒ UCO bank goes with Kanpur. [For S] The one who has applied for Corporation Bank is neither from Noida nor from Kanpur

⇒ Corporation bank goes with Patna. [For R] ⇒ OBC for Noida. Person

Gender

Bank

City

A

M

BOB

Delhi

G

M

OBC

Noida

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M

BOI

Gurgaon

R

M

Corporation

Patna

S

F

UCO

Kanpur

Clearly, S, L and N are females. 78 | P a g e

1. Candidate Candidates: s: A, G, G, L, N, N, P, Q, R and S [5 males, males, 3 fema females] les] Banks: BOB, BOI, Dena Bank, UBI, OBC, Indian Bank, Corporation Bank and UCO City: Jaipur, Delhi, Noida, Kanpur, Patna, Ranchi, Gurgaon and Ghaziabad 1. P has applied for Indian Indian Bank from Ghaziabad. Ghaziabad. G has applied for OBC. His sister L has applied for Dena Bank from Jaipur.

⇒ G is male,


⇒ N is female.


Gender

Bank

A

City Patna ×

G

M

OBC

L

F

Dena

N

F

UBI

Jaipur

P

Indian Bank

Ghaziabad

Q


R S

Kanpur



Also, N is from Ranchi (only female female left) Person

Gender

A

M

G

M

OBC

L

F

Dena

Jaipur

N

F

UBI

Ranchi

79 | P a g e

Bank

City Patna ×

P

M

Indian Bank

Ghaziabad

Q

M


R

M

S

F

Kanpur





Gender

Bank

City

A

M

BOB

Delhi

G

M

OBC

Noida

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M

BOI

Gurgaon

R

M

Corporation

Patna

S

F

UCO

Kanpur

a) A – UBI– Ranchi

⇒ False

b) R – Corporation Bank – Noida c) L – UCO Bank – Jaipur d) G – OBC – Noida

⇒ False

⇒ False

⇒ True.

Hence, G – OBC – Noida is correct. 80 | P a g e

2. Candidate Candidates: s: A, G, L, L, N, P, Q, R and and S [5 males, males, 3 female females] s] Banks: BOB, BOI, Dena Bank, UBI, OBC, Indian Bank, Corporation Bank and UCO City: Jaipur, Delhi, Noida, Kanpur, Patna, Ranchi, Gurgaon and Ghaziabad 1. P has applied for Indian Indian Bank from Ghaziabad. Ghaziabad. G has applied for OBC. His sister L has applied for Dena Bank from Jaipur.

⇒ G is male,


⇒ N is female.


Gender

Bank

A

City Patna ×

G

M

OBC

L

F

Dena

N

F

UBI

Jaipur

P

Indian Bank

Ghaziabad

Q


R S

Kanpur




Gender

A

M

G

M

OBC

L

F

Dena

Jaipur

N

F

UBI

Ranchi

81 | P a g e

Bank

City Patna ×

P

M

Indian Bank

Ghaziabad

Q

M


R

M

S

F

Kanpur





Gender

Bank

City

A

M

BOB

Delhi

G

M

OBC

Noida

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M

BOI

Gurgaon

R

M

Corporation

Patna

S

F

UCO

Kanpur

Clearly, A applied for BOB. 3. Candidate Candidates: s: A, G, L, L, N, P, Q, R and and S [5 males, males, 3 females females]] Banks: BOB, BOI, Dena Bank, UBI, OBC, Indian Bank, Corporation Bank and UCO

82 | P a g e

City: Jaipur, Delhi, Noida, Kanpur, Patna, Ranchi, Gurgaon and Ghaziabad 1. P has applied for Indian Indian Bank from Ghaziabad. Ghaziabad. G has applied for OBC. His sister L has applied for Dena Bank from Jaipur.

⇒ G is male,


⇒ N is female.


Gender

Bank

A

City Patna ×

G

M

OBC

L

F

Dena

N

F

UBI

Jaipur

P

Indian Bank

Ghaziabad

Q


R S

Kanpur




Gender

A

M

G

M

OBC

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M


R

M

83 | P a g e

Bank

City Patna ×

S

F

Kanpur





Gender

Bank

City

A

M

BOB

Delhi

G

M

OBC

Noida

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M

BOI

Gurgaon

R

M

Corporation

Patna

S

F

UCO

Kanpur

Clearly, G belongs to Noida. 4. Candidate Candidates: s: A, G, L, L, N, P, Q, R and and S [5 males, males, 3 female females] s] Banks: BOB, BOI, Dena Bank, UBI, OBC, Indian Bank, Corporation Bank and UCO City: Jaipur, Delhi, Noida, Kanpur, Patna, Ranchi, Gurgaon and Ghaziabad 1. P has applied for Indian Indian Bank from Ghaziabad. Ghaziabad. G has applied for OBC. His sister L has applied for Dena Bank from Jaipur. L is female. 84 | P a g e

⇒ G is male,

N has applied for UBI. (And her friend)

⇒ N is female.


Gender

Bank

A

City Patna ×

G

M

OBC

L

F

Dena

N

F

UBI

Jaipur

P

Indian Bank

Ghaziabad

Q


R S

Kanpur




Gender

Bank

City

A

M

G

M

OBC

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M


R

M

S

F

Patna ×

Kanpur

100. 100. Only bank left for Q are are BOB or BOI but the one who belongs to Delhi has applied for BOB.

⇒ Q applied for BOI. Only cities left: Delhi, Noida and Patna. 85 | P a g e

The one who has applied for UCO Bank has applied neither from Patna nor from Noida.



Gender

Bank

City

A

M

BOB

Delhi

G

M

OBC

Noida

L

F

Dena

Jaipur

N

F

UBI

Ranchi

P

M

Indian Bank

Ghaziabad

Q

M

BOI

Gurgaon

R

M

Corporation

Patna

S

F

UCO

Kanpur

Because, L is female while all others are males. So, L is odd-one out. Here is the question paper of this answer key:

Live Leak - RBI Assistant Prelims Model Question Paper

86 | P a g e

Ans Key Rbi Assistant Prelims 2017 PDF

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