moodle_1701
Gaurav Singh
ANALOG ELECTRONIC CIRCUITS My home home ► My course courses s ► Managed Managed Course Courses s ► Semest Semester er 1701 1701 ► 1701-E 1701-ELL3 LL304 04 ► Assign Assignmen ments ts ► Assignment 1 Started on State Completed on Time taken Grade Feedback
Saturday, Saturday, 5 August 2017, 10:51 PM Finished Friday, 11 August 2017, 7:27 PM 5 days 20 hours 10.00 out of 10.00 ( 100%)
Great!
Question 1
Consider a non-ideal diode with the standard diode equation.
Correct
changes by 1.3 milli-volt, what is the change in
Mark 1.00 out of 1.00 Flag question
Assume
is 1.6 milli-amperes. If
? Give your answer in micro-amperes.
26 milli-volts.
Answer: 80
Correct! The standard equation for the diode is:
Splitting up the equation into its operating point and small-signal parts,
This gives:
Plugging in values:
+
The correct correct answer is: 80 /- 0.8
Question 2
Correct Mark 1.00 out of 1.00
In the circuit below, the diode has a cut-in voltage of 0.7 volts.
Flag question
is 7 volts, through
and
are 0.1 and 3.1 kilo-ohms respectively. What is the current
? Give your answer in milli-amperes.
Answer: 2.1875
Correct!
If the diode is ON, then the drop across the diode is 0.7 volts. Then a KCL at the anode (negative terminal) of the diode will give:
where
is the current through the diode. The above gives
of -4.97, a negative current,
which is not possible. Therefore the diode is OFF. Given that the diode is OFF, the current through
is
or 2.1875 milli-
amperes. +
The correct answer is: 2.1875 /- 0.021875
Question 3
In the circuit below, the n-channel MOS device operates according to the model:
Correct Mark 1.00 out of
where
is 36 milli-siemens per volt and
is 0.9 volts.
1.00 Flag question
If
is 1.2 volts and
Answer: 43.2
is 2 milli-volts, what is
? Give your answer in micro-amperes.
Correct!
Or, in other words,
+
The correct answer is: 43.2 / - 2.16
Question 4
In the circuit above, as we apply a small signal voltage,
Correct
through the circuit. What is the small signal resistance of the circuit? Give your answer in
Mark 1.00 out of 1.00 Flag question
, a small signal current
flows
ohms. Answer: 46.29
Correct! For a small signal
, a small signal current
flows through the
circuit. This means that the effective small signal resistance of the circuit is:
+
The correct answer is: 46.296296296296 /- 2.3148148148148
Question 5
In the circuit below, for the nMOS device
Correct
volts as above.
is 36 milli-siemens per volt as above,
is 0.9
Mark 2.00 out of 2.00 Flag question
is 1.08 kilo-ohms. Consider the device model as given above. What is the current, Give your answer in milli-amperes.
?
Answer: 2
Correct!
Therefore:
Solving the above quadratic, we obtain the value of I_D. There will be two solutions. The larger of the two solutions is unreasonable because the corresponding is negative.
+
The correct answer is: 2 / - 0.1
Question 6
In the circuit below, the p-channel MOS device operates according to the model:
Correct Mark 1.00 out of
where
is 34 milli-siemens per volt and
is 1.4 volts.
1.00 Flag question
If
is 1.6 volts, and
is 5 milli-volts, what is the small signal current
? Give your
answer in micro-amperes. The convention for current is to measure the current going into a node. For example, the current going into the drain. Answer: 102
Correct!
Or, in other words,
is
+
The correct answer is: 102 /- 5.1
Question 7
In the circuit above, as we apply a small signal voltage,
Correct
through the circuit. What is the small signal resistance of the circuit? Give your answer in
Mark 1.00 out of 1.00 Flag question
, a small signal current
flows
ohms. Answer: 49.01
Correct!
For a small signal
v x,
a small signal current
i d
= 2 K (V X − V T ) ⋅ v x flows through the circuit.
This means that the effective small signal resistance of the circuit is: r o
=
1 2 K (3.3− V X − V T )
+
The correct answer is: 49.019607843137 /- 2.4509803921569
Question 8
In the circuit below, for the pMOS device \(K\) is 34 milli-siemens per volt as above, \(V_T\)
Correct
is 1.4 volts as above.
Mark 2.00 out of 2.00 Flag question
\(R_D\) is 0.88 kilo-ohms. Consider the device model as given above. What is the magnitude of the current, \(I_D\)? Give your answer in milli-amperes. The convention in analog electronics is that positive current flows from the top of the page to the bottom of the page.
Answer: 1.88
Correct!
\(V_{SG} = 3.3 - I_S R_D\) where \(I_S = -I_D\) is the positive current flowing into the source. Therefore: \(K(3.3 - I_S R_D - V_T)^2 = I_S\) Solving the above quadratic, we obtain the value of I_S. There will be two solutions. The larger of the two solutions is unreasonable because the corresponding \((V_{GS} - V_T) = (3.3-I_S R_D - V_T)\) is negative.
+
The correct answer is: 1.9 /- 0.095
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