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Calculation of the crack width in concrete
Design code BS 8110 & BS 8007
INPUTS Concrete strength Reinforcement yeild strength Modulus of elasticity of reinforcement steet
Fcu Fy Es As b h d
= = = = = = =
40 420 200000
Mpa Mpa Mp a
1005 1000 500 562
mm mm mm mm
Co S DIA acr Ms
= = = = =
75 125 25 95
mm mm mm mm
298
kN.m
Eco α P X Z Fs Fc ε1
= = = = = = = =
4700xSQR 4700xSQRT(f'c T(f'c)) Es / Eco As / bd (-αp (-αp + Sqrt((αp)^2 + 2αp)) 2αp )) x d d - X/3 Ms / (As x Z) Fs x As / (0.5xbxX) (F (Fs /Es) x (h-X) / (d-X)
ε2 ε2 ε2 ==> ε2 εm
= = = = =
b x (h-X)^2 / (3xEsxAsx(d-X)) 1.5 x b x (h-X)^2 / (3xEsxAsx(d-X)) 0.000237 ε1 - ε2
Reinforcement area As shown in the provided figure As shown in the provided figure As shown in the provided figure Minimum clear cover of the tension
2
reinforcement Maximum bar spacing Bar diameter As shown in the provided figure Applied service moment
CALCULATIONS Modulus of elasticity of concrete Modular ratio Reinforcement ratio Depth of the nutral axix lever arm Actual reinforcement stress Actual concrete stress Strain at the soffit of concrete Strain due to the stiffening effect of concrete between cracks: for crack width of 0.2mm for crack width of 0.1mm Average strain for crack width calculation
