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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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Capítulo 5 y 6
Sheet Music
5: ejercicios (7, ( 7, 8,10, 11, 11, 19, 22), 22), capítulo capítulo 6 ejercicios ( 6, 7, 7, 8, 10 10))
7. Considere la siguiente inor!aci"n relacionada con tres trata!ientos en un #C$% T1 y´
T2 y´
&81%06
1
s1& 17%05 n1=32
T3 y´
&78%56
2
S2&15%' n2 =16
&81%87
'
S'&1%'6 n3=16
a. resente la ta*la de $+-$ para este ensayo e interprete los resultados% $+./ -$3$+4$
#
Origen de variaciones
las
S.C.
ntre grupos
99,07
#ent entro de de lo los gr grupos
15676, 76,20
otal
15775,27
G.l. 2 61
C.M.
F
Pvalor
F crítico
9,5
0,19
0%8'
',15
256,99
6'
Conclusió Conclusión: n: Con un niel de signiicancia del 0%05 ay eidencia estadística para n recaar la ip"tesis nula, por lo tanto los trata!ientos no tienen eecto signiicatio so* la aria*le respuesta% b. Intervalos de conian!a "ara la #edia
Master your semester with Scribd ´Y −Y ´ ¿ ( & The New York Times •
1
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3
Special offer for students: Only $4.99/month. (81.06 −81.87 )± t ( 0.025,61 )
√
256.99 31
+
256.99 16
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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´ Y
Sheet Music
•
´ 2) (¿ ¿ 1−Y ¿
(81.06 −81.87 )± t ( 0.025,15 0.025,15 .99 ) (81.06 −81.87 )± 1.99
√
256.99 32
√
+
256.99 31
+
256.99 16
256.99 16
(−7.31 ; 12.31 )
Con un 95 de coniana se esti!a ue la dierencia entre los trata!ientos 1 y 2 es entre −7.31 ; 12.31 % or lo tanto se concluye ue la μ 1= μ 2 %
´ Y
•
´ 3) (¿ ¿ 2−Y ¿
0.025,15 .99 ) (78.56− 81.87 )± t ( 0.025,15
(78.56− 81.87 )± 1.99
√
256.99 16
√
+
256.99 16
+
256.99 16
256.99
(−14.64 ; 8.02) Master your semester with Scribd & The New York Times
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Useful Not useful Cancel anytime. Con unOnly 95 de coniana se esti!a ue la dierencia entre los trata!ientos 1 y 2 es Special offer for students: $4.99/month. 14.64 ; 8.02
μ 2= μ 3
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Anexo D. Matriz de Muestreo
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γ & ij
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Determinación de Los Niveles de
µ <
τ < ε i
ij
& 1,2,',,5% j & 1,2,',,5,6,7% i
#"nde:
µ
es la !edia general del e=peri!ento,
trata!iento y ε esi!a replica%
ij
τ
i
es el eecto del i>es
es el error e=peri!ental relacionado con el i>esi!o trata!iento y la
b. ?ije la ip"tesis nula tanto si!*"lica!ente co!o en pala*ras% roponga el e=peri!en ue ue dise@ado Apro*a*le!enteB para jugar esta ip"tesis% 0: D1&D2&D'&D&D5 i: Di ≠ D j para algEn i ≠ j, i & 1,2,',,5% F j & 1,2,',,5,6,7% 0: /as !edias de los trata!ientos no presentan dierencias signiicatias% 1: $l !enos un par de !edias del e=peri!ento diieren entre sí%
e reali" un e=peri!ento usando 5 trata!ientos, con 7 repicas por cada uno, con el You're Reading a Preview de encontrar el trata!iento ue tiene un !ejor eecto so*re la aria*le respuesta% , pa analiarlos se realio una ta*la de $+-$% Unlock full access with a free trial. Download en *% With Free Trial c. Gugue la ip"tesis nula planteada
o: D1&D2&D'&D&D5 i: Di ≠ D j para algEn i ≠ j $+./ # Master your semester with Scribd -$3$+4$ de las & The NewOrigen York Times variaciones S.C. G.l. Special offer for students: Only $4.99/month.
ntre grupos
2
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C.M. 61
Not useful F Cancel anytime. Pvalor F crítico 6%8 2 69 ' 15
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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a% #escri*a los actores, los nieles, las unidades e=peri!entales, la aria*le respuesta una aleatoriaci"n correcta para este dise@o%
Factores: tipo de e!paue al ue es so!etida la carne tipo !ilan &iveles: cada uno de los tipos de e!paueF copor, HiopacI, Cry>0>ac y opa 20 unidades de c 'nidades e("eri#entales: )ariable res"uesta: de pJrdida en peso respecto al peso in *leatori!ación: ara este e=peri!ento se pueden asignar nE!eros al aar a cada una d las unidades de carne entre el 1 y el donde cada nE!ero representa uno de lo trata!ientos y a su e junto al nE!ero anterior se pude indicar otro nE!ero entre lo nE!eros 1 y 5 !ediante el cual se esta*lesa su posici"n co!o repetici"n You're Reading a Preview
para analiar datos% b. speciiue el dise@o y el !odelo Unlock full access with aestos free trial. l dise@o se trata de un dise@o co!pleta!ente aleatoriado (#C$) cuyo !odelo es: Download With Free Trial
yij & D < Ki < Lij
#"nde: yij representa el alor asignado a la aria*le respuesta en la i>esi!a replica y esi!o trata!ientoF D representa la !edia general del e=peri!entoF K i representa el eec del i>esi!o trata!iento y L ij el error e=peri!ental asignado a la unidad e=peri!en Free Foron 30this Days Sign up to vote title tratada con la i>esi!a replica y j>esi!o trata!iento% Read Not useful Useful Cancel anytime.
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#entro de los grupos otal
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
'1,07
16
79,09
19
1,9
Conclusión: con un niel de signiicancia de 0,05 ay eidencia estadística para reca la ip"tesis nula, por tanto se concluye ue por lo !enos un par de !edias present dierencias signiicatias entre sí%
d. Calcule un interalo de coniana del 95 para la perdida pro!edio de peso con enoltura opac%
y´ i . ±t
(
α
2.532 ± t
M2),(n>1)a%
(0%025,16) N
¿
√
√
CME
¿
1,94 5
2.532 ± 0.49018206∗0.62318376
You're&Reading a Preview (1%21, '%85)
Unlock full access with a free se esti!a uetrial. los alores de la pJrdida de pes Conclusión: con un 95 de coniana de la carne !ilanesa despuJs de 5 día de e!pacada *ajo el trata!iento opac est;n e Download With Free Trial el interalo (1%21, '%85)%
e. Co!pare la pJrdida de peso pro!edio entre copor y HiopaI%
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o: D1&D 2 i: Di ≠ D j
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t ( 0.025,16 )
√
of 23
Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
2 ( 1.94 ) 5
&1.$
Conclusión: $l co!parar los alores >0%6 y 1%86 se eidencia ue con una signiicanc de 0%05 las !edias: D 1 (icopor), y D 2 (sopaI), no presentan dierencias signiicatias%
. Calcule el nE!ero de rJplicas para un e=peri!ento si!ilar suponiendo una potencia d 0%80% D1& 6,072 F D2&6,5F D'&5,082F D&2,5'2 #"nde: 1& copor, 2& HiopaI, '& Cry>0>-ac y & opaI Dt &5,0565 K1 &6,072 > 5,0565 &1,0155 K2&6,5 > 5,0565&1,8'5 K'&5,082 > 5,0565&0,0255 K&2,5'2 > 5,0565&>2,525 a
τi =¿ ∑ = i 1
2
9,60576'
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-ariana& O2&',95 n ɸ Master your semester with ɸScribd 2%' 1%55 5 York Times '%0' 1%7 & The New 2
' 1%82 Special offer for students: Only $4.99/month.
1%'5
(n>1) P potencia Read Free Foron 30this Days 12 15vote Sign up to title 0%85 16 2' Not useful 0%77 Useful Cancel anytime. 8 50 0%5
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',21 ,27 ',81 ,02 ',08 ,72 ,0' ,07 ',8'
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
',89 ',6 ',9 ',58 ,0' ',68 ',76 ',91 ','2 ,21 ',86 ,02
',99 ',61 ',55 ',1 ',82 ,11 ',6 ',9 ',99 ',9 ','5
a% sta*leca el !odelo lineal, eectuar el $+-$ correspondiente para estos datos intJrprete los resultados% Qodelo: Y ij & μ < s i < Y ij
si ϵ
ij
ϵ
ij
You're Reading a Preview
Unlock full access with a free trial. & ectiidad de las distintas estaciones de !uestreo
Download Free Trial & ectiidad de la i>Jsi!a estaci"n deWith !uestreo
&rror e=peri!ental en la i>Jsi!a estaci"n de !uestreo en la j>Jsi!a rJplica
Tabla de *&)*
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rata!ientos
2
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Probabilida Valor críi F Useful Cancel anytime. d Not useful !ara F
0,072'815 0,7176558 7 0,9'9209 ',2256
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( y i .− y j . ) ± t α , ( N − a) 2
of 23
√
Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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CME CME + ni n j
n donde: y i .
& Qedia de las o*seraciones para el ondo arenoso ('%9)
y j .
& Qedia de las o*seraciones para el !anglar ('%81)
N & otal de o*seraciones
a & +E!ero de trata!ientos ni
&otal de o*seraciones para el trata!iento con ondo arenoso
n j
& otal de o*seraciones para el trata!iento con !anglar
( y i .− y j . ) ± t α , (44 −3 ) 2
( y i .− y j . ) ± 2.0211
√
0,1008 13
0,1008 13
+
0,1008 16
You're Reading a Preview
+
Unlock full access with a free trial. 0,1008
16
Download With Free Trial
√ Master your semester with Scribd √ & The New York Times /í!ite superior& ( 3.94 −3.81 )+ 2.0211 /í!ite inerior& ( 3.94 −3.81 )−2.0211
Special offer for students: Only $4.99/month.
0,1008 13
0,1008 13
+
+
0,1008 16
= 0.8877
0,1008 0.6277 =−Free Foron 30this Days Sign up to vote title 16Read
Not useful Cancel anytime.
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Conclusión: Con un 95 de coniana se esti!a ue las dierencias entre las !edias d ondo arenoso y !anglar, no son signiicatias, ya ue dentro del interalo de coniana
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
R & 2%019(0%08'22) & 0%168
Sheet Music
y 1.
& '%1
y 2.
&'%'8
y 3.
&'%'6
'%1>'%'8 & ' '%1>'%'6 & 5 '%'8>'%1 & >' '%'8>'%'6 & 2 '%'6>'%1 & >5 '%'6>'%'8 & >2
Conclusión: se puede concluir ue la !edia del trata!iento (arenosa) prese dierencias signiicatias con respecto a los otros trata!ientos% S ue se presenta una dierencia signiicatia Jntrelas !edias del trata!iento2 (!angla y el trata!iento '(pasto !arino)%
1=. #ada la siguiente inor!aci"n, co!plete la ta*la de an;lisis de ariana y calcule lo You're Reading a Preview se escogieron aleatoria!en co!ponentes de ariana% uponga ue los 7 trata!ientos y se repitieron cuatro eces cada uno% Unlock full access with a free trial.
Tabla de *&)*.
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F de V
GL
SC
CM
"#CM$
F
P%valor
tratos rror otal
6 21 27
558717 1989'29%8 757650'%7
9'1195%8 9729%99
9'1195%8 9729%99
9%8'
0%0001
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!odelos%
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correspondiente, e=pliue cada co!ponente y e=pliue
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ij
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
es el error atri*ui*le a la T so!etida al i>esi!o trata!iento en la j>esi!a replica%
Su"uestos: 2 0: LijU+(0, σ )
1: /os residuos no se distri*uyen nor!al!ente 2 2 2 2 2 2 2 0: σ 1 =σ 2 = σ 3 =σ 4 = σ 5 =σ 6 = σ 7
1: or lo !enos un par
2
σi ≠ σj
2
ara todo i,j V1,2,',,5,6,7W
*% XYuJ ip"tesis se prue*an con el anterior an;lisisZ rue*e la ip"tesis planteada esti!e los co!ponentes de arianas%
4i"ótesis: You're Reading 0: σ a2Preview &0 σ with Unlock full access free trial. 2 a¿
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0
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con un niel de signiicancia eidencia estadística suiciente pa Conclusión: Master your semester with Scribdde 0,05 ayRead Free Foron 30 Days Sign to vote this title recaar la ip"tesis nula, por lo cual se concluye ue laup ariana entre los trata!ien & The New York Times es signiicatia% Useful Not useful Special offer for students: Only $4.99/month.
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r 0=
r 0=
r 0=
r 0=
[
16 −
4
2
of 23
+ 42 + 42 + 42 16
Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
]
7 −1
[
16 −
64 16
]
7 −1
[ 16− 4 ] 6
[ 12 ] 6
r 0= 2
2
σa
=
931195.8 −94729.99 2
= 418232.9 You're Reading a Preview Unlock full access with a free trial.
(CQtratos)& 9729%99 <2N 418232.9 & 9'1195%8
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22. los datos ue se e=presan a continuaci"n, corresponden a toneladas por ect;re de trigo (*ona)% l prop"sito ue ealuar 9 !Jtodos de control de !aleas, el nE!ero d rJplicas ue de '% l ensayo se reali" en angua (+ari@o)%
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
G
Sheet Music
F de V.
L
SC
CM
F
Pvalor
Fcriti
3$$Q+ 333 otal
8 2,867071 0,'58259' 0,'16585 0,8866869' 2,510 18 1,966667 0,8'0'70'7 26 17,81071
Conclusión: Con un niel de signiicancia del 0%05 ay no ay eidencia estadística pa recaar la ip"tesis nula% or lo tanto se concluye ue ningEn trata!iento tiene eec signiicatio so*re la aria*le respuesta *% sti!e el eecto pro!edio de cada !ata!aleas% $> $> >50 $r>21 $r> $r>1 H>$ H>
0,01818 1 0,21818 1 0,08181 5 > 0,185185 2 0,8181 5 > 0,1518518 5 0,8181 5 > 0,0518518 5 > 0,5518518 5
You're Reading a Preview Unlock full access with a free trial.
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Useful Not useful Cancel anytime. Special offer for students: Onlyde $4.99/month. l control !aleas $retit> !er au!enta 0% unidades so*re el alor pro!edio de lo de!;s trata!ientos contra las !aleas, se puede decir ue es !;s reco!enda*le e
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\ y´
Sheet Music
i%
> y´
Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
\ [ 2%89 (0%1'182521)
a%
[ ,1'8 \ y´
> y´
\ y´
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\ y´
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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ip"tesis de nor!alidad% paraReading !uestras iguales o !enores de 50 datos) Prueba de SAa"iro0Bil5 (otente You're a Preview
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le!ento 1 2 ' 5 6 7 8 9
Sheet Music
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Determinación de Los Niveles de
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1 >16,60 2,20 >11,00 >15,00 >1,0 >2,80 >12,00 >12,80 >27,20
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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y´ 1=6,072 ; y ´ 2=6,54 ; ´ y 3=5,03 ; y´ 4 =2,53
Sheet Music
y´ 4 =2,53 y´ 3=5,03 y´ 1=6,072
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y´ 2− y´ 4 =4,01 > 2,52 ( N% 4 )
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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2
5 1.94 (¿)
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T =t ( 16,0.025) √ ¿ T =( 2,1199 ) ( 0,88091 )=1,8674
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$. Considere los datos y el an;lisis del ejercicio 18 del capítulo 5% uponga ue se co!o trata!iento control el pesoDownload de los ni@os de las !adres no u!adoras% With Free Trial
e conjetura ue el peso al nacer de un ni@o est; asociado con el niel d consu!o de cigarrillos de la !adre durante el pri!er tri!estre del e!*arao% T estudio realiado en una clínica de !aternidad dio los siguientes resultados pa !adres agrupadas segEn el ;*ito de u!ar% /os datos son los pesos (en gra!o Read Free Foron 30this Days de los ni@os al nacer (3osner, 1986)% Sign up to vote title Not useful Useful anytime. +o =u!adora ?u!adoras(_1 Cancel ?u!adoras( ( 1 Special offer for students: Only $4.99/month. u!adoras s pauete) pauete) •
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Anexo D. Matriz de Muestreo
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b3$# TQ$ # CT$#3$# # CT$#3$# /H3 Q# $# ' 2''9005 779668,2 18 22 1621 189201,88 '1 25
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
Search document
l anterior gr;ico nos per!ite inerir en pri!era !edida so*re la nor!alidad de los residuos ya ue est;n cercanos al ajuste de una recta%
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-alor !;=i!o _ -alor crítico se recaa la ip"tesis de nor!alidad% 0,116 [ 0,259
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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^c _ ^n se recaa la ip"tesis de nor!alidad%
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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1
Sheet Music
189201,8831 (¿
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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Conclusión: l trata!iento 2 no diiere de los trata!ientos 1, ' y % l trata!iento 1 n diiere de los trata!ientos ', y You're 5% /a eidencia Reading a per!ite Previewconcluir ue los trata!ientos 2 5 diieren uno de otro, sin e!*argo no se a de!ostrado ue alguno es signiicatia!en Unlock full access with a free trial. dierente del 1, ' y % Download With Free Trial
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Anexo D. Matriz de Muestreo
Determinación de Los Niveles de
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Conclusión: #ado el alor crítico para la prue*a de #unnett, una ariedad considerarse signiicatia!ente dierente del control si la dierencia es !ayor
',02271% or lo tanto, solo la dierencia y´ 2− y´ 5 indica una dierencia signiicatia al s co!parada con el testigo, asi pues se concluye ue μ2− μ5
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