a) Power flus density = EIRP/(4πr2) b) Very Small Aperture Terminal
Te = Te1 + (Te2/G1) G1 = 1000 F = 15.85 Te2 = (F – 1) * T = 4306.3K Te = 204.31K
The equation of the orbit is an ellipse
Radius = 42,241km
VIT UNIVERSITY (E STD . U / S 3 OF UGC A CT 1956)
| *| + Azimuth angle can be found from: Case-(i) Earth station is in the northern hemisphere a) Satellite to the south east of the earth station
b) Satellite to the south west of the earth station.
Case-(ii) Earth station is in the southern hemisphere a) Satellite to the North east of the earth station:
(d) Satellite to the North west the earth station
Easier to make filters, amplifiers and equalizers at an intermediate frequency such as 1100MHz than at 14GHz or 11GHz.
[EIRP] = 56dbW
– the line joining the perigee and apogee through the center
of the earth.
VIT UNIVERSITY (E STD . U / S 3 OF UGC A CT 1956)
An orbit in which the satellite moves in the rotation is called a
direction as the earth’s
. The inclination angle of a prograde orbit is
between 0◦ and 90◦.
A satellite in a
moves in a direction
to the earth’s
rotation, with an inclination angle between 90◦ and 180◦.
measured in the
– the angle from ascending node to perigee,
plane. – the point where the orbit crosses the equatorial plane,
going from north to south.
The
,
i,
is the angle between the orbital plane and the
earth’s equatorial plane.
[ ] []
a) Bit Rate = 60Mbps Bit Rate in dB = 77.78dBbps b) [Eb /No] = 9.6dB [C/No] = 87.38dBHz [EIRP] = 26.8dBW
[Ao] = -44.37dB [EIRPS]U = 44.63dB
VIT UNIVERSITY (E STD . U / S 3 OF UGC A CT 1956)
Position Calculation Explanation Correcting the Receiver’s Clock Explanation
Structure Explanation Demodulation and Decoding
F1 = 7.943 G1 = 63095.73 123 F = 7.943 132 F = 7.943 231 F = 3.981 213 F = 3.9822 321 F = 2.5398 312 F = 2.5794
