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Deskripsi lengkap
bod
Determination of Biological Oxygen Demand.Full description
qertyuiop[Full description
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fhsdfhDeskripsi lengkap
Deals with the measurement of aggregate organic matter concentration in wastewater samples. BOD, ultimate BOD and BOD kinetics are discussed. Methods for the measurement of COD, DO, BOD, BOD uttima...
OXYGEN DEMAND DEFINITION • Dissolved Oxygen (DO) – the amount of oxygen that is present in the water in mg/L • Biochemical Oxygen Demand (BOD) the amount of oxygen utilized by microorganisms in oxidizing carbonaceous and nitrogenous organic matter • Carbonaceous Biochemical Oxygen Demand (CBOD) – BOD where the electron donor is carbonaceous organic matter • Nitrogenous Biochemical Oxygen Demand (NBOD) – BOD where the electron donor is nitrogenous organic matter
OXYGEN DEMAND DEFINITION • Theoretical Oxygen Demand (ThOD) the amount of oxygen utilized by microorganisms in oxidizing carbonaceous and nitrogenous organic matter, assuming that all of the organic matter is subject to microbial breakdown • BOD5 – 5-day BOD – the amount of oxygen consumed over an incubation period of 5 days • BODU – Ultimate BOD – the amount of oxygen consumed when all of the biodegradable organic matter has been oxidized. • Chemical Oxygen Demand (COD) – the amount of chemical oxidant required to completely oxidized a source of organic matter
DISSOLVED OXYGEN
BIOCHEMICAL OXYGEN DEMAND BOD = I – F where I = initial DO, mg/L F= final DO, mg/L
BIOCHEMICAL OXYGEN DEMAND
BOD = (I – F)D where D = dilution represented as fraction and defined as D = Total Volume of bottle Volume of Sample
BIOCHEMICAL OXYGEN DEMAND
y = L(1 – e-kt) where y = BOD at any time t in days, mg/L L = ultimate BOD, mg/L k = deoxygenation constant
BIOCHEMICAL OXYGEN DEMAND
kT k 20
( T 20 )
= 1.047 T = temperature (oC) k20 = reaction rate constant at the standard lab T kT = reaction rate at a different T
1. Given the following BOD5 test results: Initial DO 8 mg/L Final DO 0 mg/L Dilution 1 : 10 a. What can you say about BOD5? b. BOD ultimate?
2. A wastewater sample has a k1 = 0.2day-1 and an ultimate BOD = 200 mg/L. What is the final dissolved oxygen in a BOD bottle in which the sample is diluted 1:20 and wherein the initial dissolved oxygen is 10.2 mg/L?
3. Calculate the ultimate BOD of a waste that has a measured 5-day BOD of 20 mg/L, assuming a rate constant of 0.15/day.
4. A 15 ml wastewater sample is placed in a standard 300 ml bottle, and the bottle is filled with dilution water. The bottle had an initial DO concentration of 8 mg/L and a final DO concentration of 2 mg/L. A blank run in parallel showed no change in DO over the 5-day incubation period. The BOD reaction rate coefficient for the waste is 0.4/day. Calculate the 5-day BOD and the ultimate BOD of the wastewater.
5. A “midnight dumper” discharge a tank truck full of industrial waste in a gravel pit. The truck was spotted there 3 days ago, and a pool of pure waste remains. A laboratory technician determined that the waste has a 5-day BOD 80 mg/L with a rate constant of 0.1/day. Three factories in the vicinity generate organic wastes: a winery (ultimate BOD = 275 mg/L), a vinegar manufacturer (ultimate BOD = 80 mg/L), and a pharmaceutical company (ultimate BOD = 200 mg/L). Determine the source of the waste.
