Its the KUMON Maths assessment answer sheet if you apply for the Franchise.
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MATHS SAMPLE TEST ANSWERS
The maths prociency test consists of 25 questions taken from the Kumon maths programme levels A to I. Candidates will have a maximum of 40 minutes to complete the test and they will need to show good prociency in their use of basic addition, subtraction, multiplication, division, fractions, algebra and solving equations. Here are some examples of the type of questions contained in the test.
Kumon Europe and Africa
MATHS SAMPLE TEST ANSWERS KUMON APPLICANT PROFICIENCY TEST
Calculate the following expressions: LEVEL A
1.
18 + 9 = 27
LEVEL A
2.
14 - 9 = 5
LEVEL B
3.
+399 +402 +801
LEVEL B
4.
+835 - 595 +240
LEVEL C
5.
72 ÷ 8 = 9
6.
206 3 618
LEVEL C
LEVEL D
7.
+406 x 38 15428
LEVEL D
8.
29 R 259 273 8176
If 29 with wrong remainder, ½ point. If decimal or fraction, no penalty.
2
MATHS SAMPLE TEST ANSWERS KUMON APPLICANT PROFICIENCY TEST
Completely reduce the following number: LEVEL D
9.
45 = 72
5 8
Calculate the following expressions. (If answer is not in mixed number format, no penalty) LEVEL E
10.
3+3 = 1 7 4 5 20
LEVEL E
11.
+7 3 - 6 5 = 3 8 8 4
LEVEL E
12.
+2
5 x 12 = 34 6
LEVEL E
13.
1.25 ÷ 2 1 = 7 7 12
LEVEL E
14.
2
1 5 ÷ 2.8 = 3 6
LEVEL F
15.
+6 3 - 1 5 - 1 = 4 5 4 6 2 12
3
MATHS SAMPLE TEST ANSWERS KUMON APPLICANT PROFICIENCY TEST
16.
2 2 ÷ 1 7 - 11 = 7 15 17 15 9
17.
6 1 -2 2 + 13 = 5 7 3 5 10 30
18.
2 - 17 ÷ 8 1 x +1 13 20 8
19.
- (-2) + (-0.93) = 1.07
LEVEL F
1 = 12
LEVEL F
LEVEL F
LEVEL G
4
MATHS SAMPLE TEST ANSWERS KUMON APPLICANT PROFICIENCY TEST
Simplify or solve each expression below.
20.
4 x + 9 = -3
LEVEL G
x = -3
21.
(-3a + b ) + (-2a + 5b ) = -5a + 6b
LEVEL G
Solve each equation below.
22.
2(3 x - 4) = 3 x - 11
LEVEL G
x = -1
If incorrect distributive property, ½ point. If incorrect sign, ½ point.
23.
2 x - 10 = x + 5 3 3
LEVEL G
x = -45
5
MATHS SAMPLE TEST ANSWERS KUMON APPLICANT PROFICIENCY TEST
Solve the equations.
24.
{
10 x + 3 y = 27
LEVEL H
3 x - 5 y = 73 ( x, y ) = (6, -11)
Many ways to begin problem, easiest to eliminate y-term, but could eliminate x-term or solve by substitution. If incorrect sign, ½ point.
