echanical Engg. Blog | CAD-CAM-CAE C AD-CAM-CAE Blog | Civil Engg. Blog-Pramit Kumar Senapati » Interview-FAQs » MECHANICAL ENGINEER INTERVIEW F.A.Q MECHANICAL ENGINEER INTERVIEW F.A.Q MECH ENGINEERS INTERVIEW STUFF Most common Question You can expect!! What are you doing nowadays? They are looking for your mental attitude by asking you this question. If you are finding job, you should straight forward tell them the truth. They will ask for the reason why there is delay in getting job? You should tell the correct reason behind it. They actually find whether candidate is right person with right attitude or not. Do not give meaningless answer. They will find the pit hole in it and mark them as negative points. If you are working somewhere else, tell the comp lete details, do not hide anything. an ything. They will further ask you about company and designation of yours and some question related to it measure your behavior in that company compan y or professional life. What is your favorite subject in Mechanical engineering? Just be prepared for this question. This is the moment where you can prove yourself as sound in knowledge by saying your favorite subject. Normally they are looking for the subject in which their company is based on. If you are applying for the design job and you tell them thermal science as favorite subject, there is no problem. They will just check whether you are speaking truth or not. Do not tell them your favorite subject is Machine Design. If they keep throwing question regarding Machine Design, you will be caught. Do not worry if you tell other than the subject of company. Be true to yourself. You will be trained once you will be recruited. What was your project topic during Mechanical engineering? They will looking for leadership and overall ove rall quality in this question. If you did project in group work, they will find out your leadership quality b y related question. What was your role? How much time it has taken to complete the project? What is the role of guide in the project? Thus they will measure you. How do you see yourself after 5 years from now? They want leaning and growth as your aim in this question. Do not tell I want to be General Manager or higher post in short time. It is joke actually. Tell the systematic plan for pursuance of your goal. What are the software you know? You should have basic software knowledge to be used in mechanical engineering work. You should know AutoCAD, Pro-Engineer (Creo ),NX ,CAT IA,Solidworks and one Analysis software like ANSYS. Basic Technical Questions: 1. Define bending moment? Bending point is nothing but if a force is applied on body away from one fixed point then body
bends with fixed end support. This type of force is known as bending moment. M = d*f where f = forced applied and d = distance from fixed end. 2. Differentiate planner machine and shaper machine? In Planer machine tool has stationary and work piece is hold tightly on table that is responding in nature. It perfectly suits for Heavy duty operation. Large cutting force can be transferred to table In Planner. In Sharper machine tool has some responding motion and work piece holds tightly on stationary table. It perfectly suits for light duty operation. Large cutting force is moved to tool in shaper large. 3. In mechanical engineering filed, give thermodynamics significance? All the systems of mechanical engineering are studied using thermodynamics. In general, we get mechanical work by heat energy. The best example in this case is automobiles. Thus, it is very much essential for all the mechanical engineers. 4. Give the abbreviations of DCS, SCADA and HMI? • DCS – distribution Control System • SCADA – supervisory Control and Data Acquisition • HMI – Human Machine Interface 5. How knuckle pin failure occurs? Overloading is considered as the common failure. Operating application forces generate some loads that exceed clamp load and joint work fails terribly. It occurs because o f twisting moment and shear forces. 75-99% Probable Questions : What are the different types of fits? Explain? On the basis of Indian standards fits can mainly be categorized into three groups: > Clearance Fit: These types of fits are characterized by the occurrence of a clearance between the two mating parts. The difference between the minimum size of the hole and the maximum size of the shaft is called the minimum clearance, the difference between the maximum size of the hole and the minimum size of the shaft is known as maximum clearance. > Interference Fit: In these types of fits the size of the mating parts are predefined so that interference between them always occurs. The tolerance zone of the hole is completely below the tolerance zone of the shaft. > Transition Fit: As the name suggests these type of fit has its mating parts sized limited to allow either clearance or interference. The tolerance zone of the hole and the shaft overlaps in case of such fits. For a shaft designated as 40 H8/f7, calculate the tolerances. Given: Shaft designation = 40 H8/f7 The shaft designation 40 H8/f 7 means that the basic size is 40 mm and the tolerance grade for the hole is 8 ( i. e. I T 8) and for the shaft is 7 ( i. e. I T 7). Since 40 mm lies in the diameter steps of 30 to 50 mm, therefore the geometric mean diameter, D = Square root of (30 x 50) = 38.73 mm We know that standard tolerance unit, i = 0.45 x Cube root of (D) + 0.001 D i = 0.45 × 3.38 + 0.03873 = 1.559 73 or 1.56 microns i = 1.56 × 0.001 = 0.001 56 mm …(1 micron = 0.001 mm) The standard tolerance for the hole of grade 8 (IT8) = 25 i = 25 × 0.001 56 = 0.039 mm The standard tolerance for the shaft of grade 7 (IT7) = 16 i = 16 × 0.001 56 = 0.025 mm
What are the factors that can affect the Factor of safety selection? The factor of safety is used in designing a machine component. Prior to selecting the correct factor of safety certain points must be taken into consideration such as: > The properties of the material used for the machine and the changes in its intrinsic properties over the time period of service. > The accuracy and authenticity of test results to the actual machine parts. > The applied load reliability. > The limit of stresses (localized). > The loss of property and life in case of failures. > The limit of initial stresses at the time period of manufacture. > Th e extent to which the assumptions can be simplified. The factor of safety also d epends on numerous other considerations such as the material, the method of manufacturing , the various types of stress, the part shapes etc. What is heat treatment and why is it done? Heat treatment can be defined as a combination of processes or operations in which the heating and cooling of a metal or alloy is done in order to obtain desirable characteristics without changing the compositions. Some of the motives or purpose of heat treatment are as follows: > In order to improve the hardness of metals. > For the softening of the metal. > In order to improve the machinability of the metal. > To change the grain size. > To provide better resistance to heat, corrosion, wear etc. Heat treatment is generally performed in the following ways: > Normalizing > Annealing > Spheroidising > Hardening > Tempering > Surface or case hardening What are the rules that must be kept in mind while designing castings? Some of the points that must be kept in mind during the process of cast designing are as follows: > To avoid the concentration of stresses sharp corners and frequent use of fillets should be avoided. > Section thicknesses should be uniform as much as possible. For variations it must be done gradually. > Abrupt changes in the thickness should be avoided at all costs. > Simplicity is the key, the casting should be designed as simple as possible. > It is difficult to create true large spaces and henceforth large flat surfaces must be a voided. > Webs and ribs used for stiffening in castings should as minimal as possible. > Curved shapes can be used in order to improve the stress handling of the cast. What are the points that should be kept in mind during forging design? Some of the points that should be followed while forging design are: > A radial flow of grains or fibers must be achieved in the forged components. > The forged items such as drop and press forgings should have a parting line that should divide the forging into two equal halves. > The ribs in a forging should not be high or thin. > In order to avoid increased die wear the pockets and recesses in forgings should be minimum. > In forgings the parting line of it should lie as far as possible in a single plane. > For ease of forging and easy removal of forgings the surfaces of the metal should contain sufficient drafts. Describe briefly the different cold drawing processes. Some of the important cold drawing processes are as follows: > Bar and Rod Drawing: In the case of bar drawing the hot drawn bars are at first pickled, washed and coated to prevent oxidation. Once this is done a draw bench is used for the process of cold drawing. In order to
make an end possible to enter a drawing die the diameter of the rod is reduced by the swaging operation. This end is fastened by chains to the draw bench and the end is gripped by the jaws of the carriage. In this method a high surface finish and accuracy dimensionally is obtained. The products of this process can be used directly without any further machining. > Wire Drawing: Similar to the above process the bars are first pickled, washed and coated to prevent any oxidation. After this the rods are passed through sev eral dies of decreasing diameter to provide a desired reduction in the size ( diameter ). The dies used for the reduction process is generally made up of carbide materials. What are the different theories of failure under static load, explain briefly? The main theories of failure of a member subjected to bi-axial stress are as follows: > Maximum principal stress theory ( Rankine’s theory): This theory states that failure occurs at a point in member where the maximum principal or normal stress in a bi-axial system reaches the maximum strength in a simple tension test. > Maximum shear stress theory ( Guest’s or Tresca’s theory): This theory states that failure occurs when the biaxial stress reaches a value equal to the shear stress at yield point in a simple tension test. > Maximum principal strain theory ( Saint Venant theory): This theory states that failure occurs when bi-axial stress reaches the limiting value of strain. > Maximum strain energy theory ( Haigh’s theory): This theory states that failure occurs when strain energy per unit volume of the stress system reaches the limiting strain energy point. > Maximum distortion energy theory ( Hencky and Von Mises theory): This theory states that failure occurs when strain energy per unit volume reaches the limiting distortion energy. What are the assumptions made in simple theory of bending? The assumptions made in the theory of simple bending are: > The material of the beam is homogeneous this implies that it is uniform in density, strength and have isotropic properties meaning possessing same elastic property in all directions. > Even after bending the cross section of the beam remains constant. > During the initial stages the beam is straight and unstressed. > All the stresses in the beam are within the elastic limit of its material. > The layers of the beam are free to contract and expand longitudinally and laterally > On an y cross section the perpendicular resultant force of the beam is zero. > Compared to the cross-sectional dimension of the beam the radius of curvature is very large. Why is stress considered important in a shaft? The following types of stresses are prevalent in shafts: > At the outermost surface of the shaft the max shear stress occurs on the cross-section of the shaft. > At the surface of the shaft on the longitudinal planes through the axis of the shaft the maximum longitudinal shear stress occurs. > At 45 degrees to the maximum shearing stress planes at the surface of the shafts the major principal stress occurs. It equals the max shear stress on the cross section of the shaft. > For certain materials where the tensile and compressive strengths are lower in measure as compared to the shear strength, then the shaft designing shou ld be carried out for the lowest strengths. > All these stresses are of significance as they play a role in governing the failure of the shaft. All theses stresses get generated simultaneously and hence should be considered for designing purposes
What do you understand by the Hooke`s Coupling what are its purposes? The Hooke`s coupling is used to connect two shafts whose axes intersect at a small angle. The two shafts are inclined at an angle and is constant. During motion it varies as the movement is transferred from one shaft to another. One of the major areas of application of this coupling is in gear boxes where the coupling is used to drive the rear wheels of trucks a nd other vehicles. In such usage scenarios two couplings are used each at the two ends of the coupling shaft. they are also used to transfer power for multiple drilling machines. The Hooke`s coupling is also known as the Universal coupling. The torque transmitted b y the shafts is given by : T= (pie/16) x t x (d) cube Where T = torque, t = shear stress for the shaft material and d the diameter of the shaft. What kind of materials should be used for shafts manufacturing? Some of the qualities that should be present in materials for shafts are as follows: > The material should have a high index of strength. > Also it should have a high level of machinability. > The material should possess a low notch sensitivity factor. > The material must also hav e wear resistant properties. > Good heat treatment properties should also be present The common material used to creates shafts of high strengths an alloy of steel like nickel is used. The shafts are manufactured by hot rolling processes and then the shaft is finished using drawing or grinding processes. Why should a chain drive be used over a belt or rope driven drive? State pro`s and con`s? The advantages of using a chain drives are: > In a chain drive no slip occurrence takes place. > The chains take less space as compared to rope or belts as they are made of metal and offer much strength. > The chain drives can be used at both short and long ranges and they offer a high level of transmission efficiency. > Chain drives can transmit more load and power as compared to belts. > A very high speed ratio can be maintained in one step of chain drives. Some of the cons of using a chain drive are: > The cost of producing chain drives is higher as compared to that of belts. > The chain drives must be serviced and maintained at regular intervals and henceforth their cost of ownership is high comparatively. What are the different types of springs and explain them briefly? Springs can be broadly classified into the following t ypes: > Helical Springs: These springs as their name suggests are in coil form and are in the shape of helix. The primary purpose of such springs are to handle compressive and tensile loads. They can be further classified into two types: compression helical spring and tension helical spring each having their own unique areas of application./ > Conical and volute springs: Both these spring types have specialized areas of usage where springs with adaptable rate accordin g to the load is required. In case of conical springs they are wound so as to have a uniform pitch while on the other hand volute springs are wound in a slight manner of a parabloid. > Torsion Springs: The characteristics of such springs is that they tend to wind up by the load. They can be either helical or spiral in shape. These types of springs are used in circuit breaker mechanisms. > Leaf springs: These types of springs are comprised of metal plates of different lengths held together with the help of bolts and clamps. Commonly seen being used as suspensions for v ehicles. > Disc Springs: As the name suggests such types of springs are comprised of conical d iscs held together by a bolt or tube. > Special
Purpose Springs: These springs are all together made of different materials such as air and water. During the design of a friction clutch what are the considerations that should be made? In order to design a friction clutch the following points must be kept in mind: > The material for the contact surfaces must be carefully selected. > For high speed devices to minimize the inertia load of the clutch, low weight moving parts must be selected. > The contact of the friction surfaces must be maintained at all the times without the ap plication of any external forces. > Provisions for the facilitation of repairs must be there. > In order to increase safety the projecting parts of a clutch must be covered. > A provision to take up the wearing of the contact surfaces must be present. > Heat dissipaters to take awa y the heat from the point of contacting surfaces must be there. What are the different types of brakes and explain them briefly? Brakes can be classified on the basis of their medium used to brake, they are as follows: > Hydraulic Brakes: These brakes as their name sug gest use a fluid medium to push or repel the brake pads for braking. > Electric Brakes: These brakes use electrical energy to deplete or create a braking force. Both the above types of breaks are used primarily for applications where a large amount of energy is to be transformed. > Mechanical Brakes: They can be further classified on the basis of the direction of their acting force: Rad ial Brakes: As their names suggests the force that acts on the brakes is of radial direction. They can further be classified into internal and external blades. Axial Brakes: In these types of brakes the braking force is acting in an axial direction as compared to radial brakes. On what basis can sliding contact bearings be classified? Explain? Sliding contact bearings can be classified on the basis of the thickness of the lubricating a gent layer between the bearing and the journal. They can be classified as follows: > Thick film bearings: These type of bearings have their working surface separated by a layer of the lubricant. They are also known as hydrodynamic lubricated bearings. > Thin film bearings: In this t ype of bearings the surfaces are partially in direct contact with each other even after the presence of a lubricant. The other name for such t ype of bearings is boundary lubricated bearings. > Zero Film Bearings: These type of bearings as their name suggests have no lubricant present between the contact layers. > Externally or hydrostatically pressurized lubricated bearings: These bea rings are able to without any relative motion support steady loads. What are the basis on which the best material for Sliding Contact Bearings manufacturing? Some of the important properties to lookout for in the material for sliding contact bearings are as follows: > Compressive Strength: In order to prevent the permanent deformation a nd intrusion of the bearing the material selected should be possess a high compressive strength to bear the max bearing pressure. > Fatigue Strength: the material selected for the bearing should be able to withstand loads without any surface fatigue cracks getting created. This is only possible if the material has a high level of fatigue strength. > Comfortability: The material should be able to adjust or accommodate bearing inaccuracies and deflections without much wear and heating. > Embeddability: The material should allow the embedding o f small particles without effecting the
material of the journal. > Bondability: The bea rings may be created by bringing together ( bonding ) multiple layers of the material. Due to the above reason the bondability of the material should be sufficiently high. > Thermal conductivity and corrosion resistance: Thermal conductivity is an essential property for bearing materials as it can h elp in quickly dissipating the generated heat. Also the material should have a level of corrosion resistance against the lubricant. Briefly explain the advantages of Cycloidal and Involute gears? The advantages of the C ycloidal gears are as follows: > Having a wider flank as c ompared to Involute gears they are considered to have more strength and hence can withstand further load and stress. > The contact in case of cycloidal gears is between the concave surface and the convex flank. This results in less wear and tear. > No interference occurs in these types of gears. The advantages of Involute gears are as follows: > The primary advantage of involute gears is that it allows the changing of the centre distance of a pair without changing the velocity ratio. > The pressure angle remains constant from start to end teeth, this results in less wear and smooth running of the gears. > The involute gears are easier to manufacture as they can be generated in a single curve ( the face and flank ). How can the reaction of support of a frame be evaluated? Generally roller or hinged support are used to sup port the frames. The conditions of equilibrium are used to determine the reaction support of a frame. The condition of equilibrium takes place when the sum of the horizontal and vertical forces sum equal to zero. The system must form a state of equilibrium even after considering the external loads and the reactions at the supports. For equilibrium to be prevalent in the system the following conditions are required to be in occurrence: > Summation of V = 0. This implies that the summation of all the forces in the vertical direction results to zero. > Summation of H = 0 . This implies that the total of all the forces acting in horizontal direction is also zero. > Summation of M = 0. The sum of all the moment of forces around a point must be zero. Explain in an orderly manner how the force in the member of a truss be detected using the method of joint. The steps required to calculate the force are as follows: > The reaction at the support has to be first calculated. > Once the reaction is calculated the direction of force of the member is made to make it tensile. On getting the result to be negative the direction assumed is wrong and this implies the force being compressive in nature. > A joint needs to be selected whose 2 members are not known. The lami`s theorem is used on the joint on which less than three forces are acting. > After the above process is complete the free body diagrams of the joint needs to be made. Since the system is in equilibrium the condition of Summation of V and H must result in zero. > After the above step the resolution of forces method needs to be used on the joint on which more than 4 forces are acting. In order to derive the torsional formulas what are the assumptions taken? The torsion equation is derived on the basis of following assumptions: > The shaft material is uniform, throughout the shaft. > Even after loadin g the shaft circular remains circular. > After
the application of torques the plain section o f a shaft remains plain. > Any twist that occurs in the shaft remains uniform and constant. > After the application o f torque the distance between any two cross-sectional references remains constant. > The elastic limit value of a shaft is ne ver exceeded even after the shear stress induced because of torque application. What are Bevel Gears and what are its types? Bevel gears are the type of gears in which the two shafts happen to intersect. The gear faces which are tooth bearing are conical in shape. They are generally mounted on shafts which are 90 degrees apart but they can be made to work at other angles as well. The bevel gears are classified into the following types on the basis of pitch surfaces and shaft angles: > Mitre Gears: These types of gears are similar to each other ie. they have the same pitch angles and contain the same number of teeth. The shaft axes intersect at 90 degrees angle. > Angular bevel gears: When two bevel gears connect at any angle apart from 90 degrees. > Crown bevel gears: When the two shaft axes intersect at an angle greater than 90 and one of the bevel gears have a pitch angle of 90 degrees they are known as crown bevel gears. > Internal bevel gears: In these type of gears the teeth on the gears is cut on the inside area of the pitch cone. What are the different values that need to be determined in order to design a cylinder for an ICE? The following values are needed to be determined: > Thickness of the cylinder wall: The cylinder walls in an engine is made witness to gas pressure and the side thrust of a piston. This results in two types of stresses: longitudinal and circumferential stress. Both the types of stresses are perpendicular to each other and hence it is aimed to reduce the resulting stress as much as possible. > Length and bore of the cylinder: The length of the cylinder and the length of the stroke is calculated on the basis of the formula: length of cylinder L = 1.15 times the length of the stroke (l). L = 1.15(l) > Cylinder flange and studs: The cylinders are always cast integral as a part of the upper crankcase or in some cases attached to it by means of nuts and bolts. The flange is integral to a cylinder and henceforth its thickness should be greater than that of the cylinder wall. The thickness of flange should generally be between 1.2t-1.4t where t is the cylinder thickness. The stud diameter is calculated b y equating gas load ( due to max pressure ) to the grand total of all the resisting forces of the studs. What are considerations taken into account while creating a piston head? The piston head is designed on the basis of the following considerations: > The crown should have enough strength to absorb the explosion pressure inside the engine cylinder. > The head must always dissipate the heat of the explosion as quickly as possible to the engine walls. The thickness of the head is calculated on the basis of another formula which takes into consideration the heat flowing through the head, the conductivity factor of the material. The temperature at the center and edges of the head. > The thickness of the piston head is calculated on the basis of the Grashoff`s formula which takes into consideration the maximum gas pressure of an explosion , the permissible bending and the outside diameter of the piston. Also Practice below Question Sets before going to interview?
1. What is mechanism? 2. How Sap is useful for mechanical engineers? 3. What is Newton law, explain it. 4. Explain the law of thermodynamics? What is a importance of it in a field of Mechanical Engineering? 5. What is Hess law? 6. What is PS? 7. What is bearing? Explain types of it. 8. What is the process flow diagram? 9. What is a time and motion theory? 10. Which is the hardest material on earth? 11. One unit of BTU has how much number of Joules? 12. Explain the procedure of operating a pump? 13. What does a pump develop, Give reason to support your answer 14. “Pipe” Explain the concept behind it 15. Explain the difference between pipe and a tube? 16. Explain the formula of heal loss in a pipe. 17. What kind of pipes are used for steam lines? 18. Who invented a four stroke engine? According to you which one is more efficient Four stroke engine and a two stoke engine and why? 19. What do you understand by the concept of 6 stroke engine? Explain how it work. 20. Explain what is torque? 21. What is the difference between torque and power? 22. Explain why diesel engine called as high torque and petrol engine as high speed engine? 23. Why heavy vehicles are made by diesel engine? 24. How does length and initial angel effect period in a simple pendulum? 25. Explain the difference between projectile motion and rocket motion? 26. According to you which one is stronger thick steel wire or thick steel wire and why? 27. Between steel copper and brass,which con duct faster heat. 28. Explain the types of sensor and their explanation. 29. What all are the mineral needed to make a car? 30. With the help of which instrument we can measure a speed in a car? 31. Advantage and disadvantage of using LPG in a car? 32. Why gas container are mostly in a cylindrical shape? 33. Explain, why re-heater is used in gas turbine? 34. How can a square section cut in lathe? 35. how many types of suspension is used in automobiles? 36. What is DTSI? Why it is used in motor bikes? 37. What are the advantages of DTSI over normal engines? 38. What is meant by gear ratio? 39. What is the ratio of specific heat of air? 40. What is the percentage of carbon present in pig iron? Some More Questions to Try !!! 1. A hollow shaft of same cross-section area as solid shaft transmits A. Same torque B. Less torque C. More torque D. Unpredictable Answer: B. Less torque 2. In a cantilever beam, maximum deflection occurs at where A. Bending moment is zero B. Bending moment is maximum C. Shear force is zero D. Slope is zero Answer: A. Bending moment is zero 3. In a rectangular beam, when width, depth and length are doubled, the bending stress
will be A. Shall remain unchanged B. Shall be doubled C. Shall become ¼ th D. Shall be halved [Type here] Answer: C. Shall become ¼ th 4. In an I – section beam, the bending moment is resisted mainly by A. Flanges only B. Web only C. Both by flanges and web D. None of the above Answer: B. Web only 5. In internal combustion (I.C.) engines, combustion of fuel takes place in A. Outside the cylinder B. Inside the cylinder C. Not in the cylinder D. None of the above Answer: B. Inside the cylinder 6. Power available at the shaft of an I.C engine is known is A. Brake horse power B. Indicated horse power C. Net indicated horse power D. Pumping power [Type here] Answer: A. Brake horse power 7. In internal combustion engine piston the maximum temperature occurs at A. Ring section B. Gungeon pin C. Bottom centre D. Top centre Answer: A. Ring section 8. A two-stroke engine is generally preferred to a four-stroke engine because A. It offers low fuel consumption B. It gives lesser shocks and vibrations
C. It can be easily started D. It has smaller size for the same output. Answer: D. It has smaller size for the same output. 9. During idling process, a petrol engine requires A. Lean mixture B. Rich mixture C. Variable mixture D. None of above Answer: A. Lean mixture [Type here] 10. Cavitation in a pipe will begin when A. Pressure at any location reaches pressure equ al to the saturated vapour pressure of liquid B. Pressure becomes more than critical pressure C. Flow is increased D. Pressure is increased Answer: A. Pressure at any location reaches pressure equ al to the saturated vapour pressure of liquid 11. Capillary action of liquid is due to the A. Viscosity of liquid B. Cohesion of liquid particles C. Surface tension D. Adhesion of liquid particles on the surface Answer: B. Cohesion of liquid particles 12. In one ton refrigeration machine, the term “one ton” implies A. One ton refrigerant is used B. One ton water can be converted into ice C. One ton ice when melts from and at 0oC in 24 hours, the refrigerating effects is equivalent to 3000 kcal/hour D. None of the above Answer: C. One ton ice when melts from and at 0oC in 24 hours, the refrigerating effects is equivalent to 3000 kcal/hou [Type here] 13. In a refrigeration cycle, the moisture content is to be removed before it enters into which system A. Cold side of system B. Evaporator
C. compressor D. condenser Answer: B. Evaporator Must have questions for All !!! 1.Introduce yourself? 2. What are your career preferences? 3. How much salary you are expecting? 4. What is your plan regarding continuing your education? 5. Tell us about your hobbies? 6. What are your strengths & weaknesses? 7. Are you ready to work in a team? 8. Can you work in stress? 9. What good things you liked in your ex boss? 10. How do you feel working on weekend? 11. Define success? 12. How good your communication is? 13. Where do you see yourself in next 2 years? 14. You like trying new things or stay with old ones? 15. Why you have applied for this position? 16. Tell us about your family? 17. Areas where you can revamp your skills? 18. What if you are not selected for this position? 19. What makes you feel that you are the best candidate for this position? 20. What you preferred, money or work? 21. Tell us about your subjects? 23. What is your greatest strength? 24. What are you looking for in a job? 25.What kind of person would you refuse to work with? 26. What is more important to you: the mone y or the work? 27. Tell me about your ability to work under pressure. 28. Do your skills match this job or another job more closely? 29. What motivates you to do your best on the job? 30. Describe your management style. 31. How do you propose to compensate for your lack of experience? 32. Describe your work ethic. 33.What qualities do you look for in a boss? 34.What position do you prefer on a team working on a project? 35. Do you have any questions for me?
