Dapat menggunakan alat ukur panjang dan membaca hasil pengukuran alat ukur panjangFull description
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Nama NPM
: Ghusaebi : 1106022894 Teknik Elektro
15. In Fig. 25-31, a 20.0 V battery is connected across capacitors of capacitances C j = C6 = 3.00,uF and C3 = Cs = 2.00C 2 = 2.00C 4 = 4.00,uF. What are (a) the equivalent capacitance j and (d) qj of capacitor Ceq of the capacitors and (b) the charge charge stored by Ceq? What are (c) V 2 and (f) q2 of capacitor 2, and (g) V3 and (h) q3 of capacitor 3? 1, (e) V 2
A) Kombinasi C 5 dan C3 = Ca
Cs= 2 uF Kombinasi rangkaian paralel Ca, C 2, & C4 = Cp’ = C4 + C2 + Ca =2+2+2 = 6 uF Kombinasi rangkaian Paralel C1 & C6 = Cp = C1 + C6 =3+3 = 6 uF Ceq =
Ceq =
Ceq = 3 uF –5
B) q = C eqV = (3.00 μF) (20.0 V) = 6.00 × 10 C
C) V1=
10 Volt
D) q1 = C 1V 1= (3.00 μF)(10.0 V) = 3.00 × 10 –5 C
E) V 2 = V – V 1 = 20 V – 10 V = 10 V F) q2 = C 2V 2 = (2.00 μF)(10.0 V) = 2.00 × 10 –5 C G) V3 + V5 = V2 dan V3 = V5 maka V3 =
=
= 5 Volt
H) q3 = C 3V 3 = (4.00 μF)(5.00 V) = 2.00 × 10 –5 C
74 You have two plates of copper, a sheet of mica (thickness = 0.10 mm, K = 5.4), a sheet of glass (thickness = 2.0 mm, K = 7.0), and a slab of paraffin (thickness = 1.0 cm, K = 2.0). To make a parallel- plate capacitor with the largest C, which sheet should you place between the copper plates? Jawab : Kita gunakan rumus C = ε 0κ A/d ∝ κ/d . Untuk memaksimalkan C kita memerlukan
material dengan nilai κ/d terbesar. Maka dari itu kita memilih mika dengan nilai κ/d =
= 54 yang merupakan nilai
terbesar sehingga C yang didapat maksimal.
15. Estimate the capacitance of the Leyden jar shown in the Figure 24-34. The figure of a man is one-tenth the height of an average man. Picture the Problem Modeling the Leyden jar as a parallel-plate capacitor, we can use the equation for the capacitance of a dielectric-filled parallel-plate capacitor that relates its capacitance to the area A of its plates and their separation (the thickness of the glass) d to estimate the capacitance of the jar. See Table 24-1 for the dielectric constants of various materials.
Kapasitas dielektrik Dimana k (konstanta dielektrik)
Luas plat dielektrik
Dimana h (tinggi jar) dan r (radius)
Substitusi ke rumus kapasitas dielektrik
Jika ketebalan 2.0 mm andradius 4.0 cm and tinggi jar 40 cm, maka :
