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Problema 7.3
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Problema 7.3
Descripción: Problema 7.3 de Mc Cormak...
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g := 2.5in L := 3.5in s := 2 in se := 1.5in
Propiedades de los tornillos d b :=
7 8
h := d b +
in
1 8
in = 1 in
Placa de 14x1/2 plg de Acero A242 Fy := 50ksi
Fu := 70ksi 2
Ag := b × t = 7 in
b := 14in
t :=
1 2
in
:= 0.9
Resistencia de diseño por Fluencia R ny :=
5
5
× Fy× Ag = 3.15 ´ 10 lbf
R ny = 3.15 ´ 10 lbf
Resistencia de diseño por fractura x :=
t 2
= 0.25 in
U := 1 -
:= 0.75
x L
= 0.929
2
An1 := Ag - 1 × h × t = 6.5in 2
An2 := Ag - 2h × t = 6 in
2
An3 := Ag - 3 × h × t = 5.5in
æ s 2 ö
æ s2 ö
e 2 ×t + 2 An4 := Ag - 5 × h × t + 2 × × t = 5.125in è 4× g ø è 4× g ø
(
2
)
An := min An1 , An2 , An3 , An4 = 5.125in 2
Ae := U× An = 4.759in R nu :=
Area neta
Area neta efectiv a
5
× Fu × Ae = 2.498 ´ 10 lbf
5
R nu = 2.498 ´ 10 lbf
×
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