In this project we are aimed at making an automatic stair climbing wheelchair with bed. A concept for a stair climbing wheelchair capable of moving in structured and unstructured environment…Full description
it can be used as referenceFull description
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The project deals with the designing and manufacturing of a tri wheeler stair climber, which can climb stairs with less effort as compared to manual work. The technical issues in designing of this vehicle are the stability and speed of the vehicle wh
MECHANICAL DEPARTMENT.
Design calculation sheet Project no:
Date:
9-Jul-2017
1
Sheet no.:
2
Computed by:
Eng / Omar Alawad
Subject:
Stairwell Pressurisation with some doors opened. Summer
Conditions :
Fire Escape on : Stair Doors: Escape Door : Building Height :
Pressure Level :
4 Floors 4 1 20.0 m 25 Pa Q1= 0.827 x AE x P1/n
1- Air volume required when all doors are closed : Q = Volume of Air Required (m3)
AE = Leakage Area from the space (m2) (m2) for Single Leaf Doors with or without Central Rebate = 0.010 (m2) for = 0.040 4 Stair Doors P = Pressure Differential = Q1 = 0.827
x
0.04
x
25 Pa
n = Leakage Factor =
25 ½
:
Q1 =
2 0.165
m3 / sec
Although the effective leakage area is known, there are other leaks we are not aware of. To account for these leaks, Q is increased by 50%, hence: Q1 = 0.165 +50%
Q1 =
0.25
m3 / s
2- Air volume required when doors are opened : Door Area = 2 Air Velocity Across Door
x =
1 0.75
= m/s
2.00 m2 ### fpm
Minimum Number of Opened Doors
= main escape doors + 10% of remaining straiwell doors = 1 + 1 Open door area = Area of escape doors + 50% of the area of the other doors = 2.00 + 1 2 m = 3.00 Q2 = A x V => Q2 = 2.25 m3 / s 3- Total Air Supplied by the fan : QT = Q1 + Q2 =>
QT =
2.5 m3 / s
=
5278 cfm
1320 cfm per floor
Design calculation sheet Project no: Subject:
Sheet no.: 7/9/2017 2 0 Stairwell Pressurisation with some doors opened. Summer
2
Date:
QT =
at
2.5 m3 / sec
1500 fpm
Duct Length =
5278 cfm
=>
f=
=
2498 l/s
0.1 "/100 ft
20.0 m
Friction Loss through duct: Friction Loss
=
Eng / Omar Alawad
Computed by:
=
=
Total Static Pressure
(Duct Length x 1.25 x 3.28 x f) 0.08 "
Total Static Pressure on Fa
= = = = = =
Total Fan Static Pressure
=
Total Fan Static Pressure Total Fan Flowrate Total Fan Power
(PD at Register + Friction Loss + Volume Damper)*30% 0.20 + 0.08 + 0.2 0.63 " 15.7 mm 156 Pa 156 + 25 181 Pa