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Strap Foundation
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Strap Foundation
STRAP FOOOTING...
Author:
Rian Ibayan
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DESIGN OF STRAP BEAM
EXT COL
1. 0 LOADS INPUT
Pw1 Mwy1 Pu1 Muy1
EXT COLUMN LOAD = 190.96 KN = 42.947 KN-m = =
IN Pw2 Mwy2
242.51 KN 59.542 KN-m
2.0 CONSIDER WEIGHT OF FOOTING
Pu2 Muy2
=
10
%
EXTERIOR COLUMN Serv!e C"#um$ L"&
=
190.96
Serv!e C
'e()* "+ ,""*$(
=
19.096
'e()* "+
=
210.056
T"*# T"*# C"$
T"*# T"*# C"$!e$*r*e& L"&
3.0 FOOTING AREA T"*# T"*# C"m$e& er*!# er*!# L"& Pw1 = 210.056 KN Pw2 = 316.602 KN
/e SC r&
Pw*
=
526.66
KN
Leng! "n# A$e" %& E'e$(%$ F%%(ng 1 = 2.10 .m L = 1.45 m L 1
= =
1.60 2.56
m .m
Leng! 2 L L 2
/emr
COMBINED AREA 1 2
=
5.)
.m
!* r&8
*.0 CENTROID OF FOOTING +WOR,ING LOAD-
:(
CG OF LOADS = P1:1 P2:2 Mwy1 Mwy2
526.65;
:(
:(
=
5.;
CG OF AREA = 1:1 2:2
:(
=
2.56
m +r"m re+ere$!e #$
=
-0.27
m
&
2.)3
m +r"m re+ere$!e #$
/e+ #$e
Leng! %& &%%(ng 1
1.6
Ce"$ /#/
Ce$*r"& "+ !"#um$ L"& X =
P1 =
2.;3
210.06
L1 2 = 0.)
R1
X1 0.)
P* =
% %& %4n
5.0 SOLING FOR STRAP BEAM FORCES +ULTIMATE FORCESEXTERIOR COLUMN 242.5
KN
0.;
M >KN-m? = 59.5
>S)er?
M
= =
0.;
/1 M1 1
/1 =
210.91
= = =
210.91 34.26 31.60
KN
KN KN-m KN
@NT COL
TERIOR COLUMN LOAD = 2;7.;2 KN = 2;.6;3 KN-m = =
371.99 40
KN KN-m
INTERIOR COLUMN #um$ L"&
=
2;7.;2
,""*$(
=
2;.7;2
e$*r*e& L"&
=
316.602
ure& T"*# re "+ +""*$( = 100 KA =
5.27
.m
"n# A$e" %& Ine$(%$ F%%(ng = 3.17 .m = 1.7; m =
1.;0 3.24
m .m
e
e
e. C% 1.*5
Leng! %& &%%(ng 2
1.)
P2 316.60
L2 2 = 0.
526.65) R2
3.15
4
0.
*.)5
INTERIOR COLUMN
372.0
KN
0.9
M >KN-m? = 40.0
>S)er? 0.9
/2 M2 2
34.26 31.60
KN-m KN
/2 =
403.59
= = =
403.59 11.56 31.60
KN
KN KN-m KN
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